题目描述
给定一个数组A[0,1,...,n-1],请构建一个数组B[0,1,...,n-1],其中B中的元素B[i]=A[0]A[1]...A[i-1]A[i+1]...A[n-1]。不能使用除法。
分别求上三角和下三角乘积
# -*- coding:utf-8 -*-
class Solution:
def multiply(self, A):
# write code here
l1, l2 = [1]*len(A), [1]*len(A)
for i in range(1, len(A)):
l1[i] = l1[i-1]*A[i-1]
for i in range(len(A)-2, -1, -1):
l2[i] = l2[i+1]*A[i+1]
res = [0]*len(A)
for i in range(len(A)):
res[i] = l1[i]*l2[i]
return res
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