基础索引与切片

作者: 庵下桃花仙 | 来源:发表于2019-01-14 22:59 被阅读8次
    In [11]: arr = np.arange(10)
    
    In [12]: arr
    Out[12]: array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])
    
    In [13]: arr[5]
    Out[13]: 5
    
    In [14]: arr[5: 8]
    Out[14]: array([5, 6, 7])
    
    In [15]: arr[5: 8]
    Out[15]: array([5, 6, 7])
    
    In [16]: arr[5: 8] = 12
    
    In [17]: arr
    Out[17]: array([ 0,  1,  2,  3,  4, 12, 12, 12,  8,  9])
    

    与 Python 内建列表不同。数组的切片是原数组的视图,意味着数据并不是被复制了,任何对于视图的修改都会反映到原数组上。

    In [22]: arr_slice = arr[5: 8]
    
    In [23]: arr_slice
    Out[23]: array([12, 12, 12])
    
    In [24]: arr_slice[1] = 12345
    
    In [25]: arr
    Out[25]:
    array([    0,     1,     2,     3,     4,    12, 12345,    12,     8,
               9])
    
    In [26]: arr_slice[:] = 64
    
    In [27]: arr
    Out[27]: array([ 0,  1,  2,  3,  4, 64, 64, 64,  8,  9])
    
    >>> a = [1, 2, 3, 4, 5]
    >>> a[0] = 6
    >>> a
    [6, 2, 3, 4, 5]
    >>> arr = a[0]
    >>> arr
    6
    >>> arr = 12345
    >>> arr
    12345
    >>> a
    [6, 2, 3, 4, 5]
    

    因为 numpy 适合处理很大的数组,如果持续复制数据,会引起内存问题。实在想要一份拷贝的话,要显式地复制数组 arr[5: 8].copy()

    在二维数组中,每个索引值对应的元素是一个一维数组。

    In [28]: arr2d = np.array([[1, 2, 3], [4, 5, 6], [7, 8, 9]])
    
    In [29]: arr2d
    Out[29]:
    array([[1, 2, 3],
           [4, 5, 6],
           [7, 8, 9]])
    
    In [30]: arr2d[2]
    Out[30]: array([7, 8, 9])
    
    In [31]: arr2d[0][2]
    Out[31]: 3
    
    In [32]: arr2d[0, 2]
    Out[32]: 3
    

    在多维数组中,可以省略后续索引值,返回降低一个维度的数组。

    In [2]: import numpy as np
    
    In [3]: arr3d = np.array([[[1, 2, 3], [4, 5, 6]], [[7, 8, 9], [10, 11, 12]]])
    
    In [4]: arr3d
    Out[4]:
    array([[[ 1,  2,  3],
            [ 4,  5,  6]],
    
           [[ 7,  8,  9],
            [10, 11, 12]]])
    
    In [5]: arr3d[0]
    Out[5]:
    array([[1, 2, 3],
           [4, 5, 6]])
    
    In [6]: old_values = arr3d[0].copy()
    
    In [7]: arr3d[0] = 42
    
    In [8]: arr3d
    Out[8]:
    array([[[42, 42, 42],
            [42, 42, 42]],
    
           [[ 7,  8,  9],
            [10, 11, 12]]])
    
    In [9]: arr3d[0] = old_values
    
    In [10]: arr3d
    Out[10]:
    array([[[ 1,  2,  3],
            [ 4,  5,  6]],
    
           [[ 7,  8,  9],
            [10, 11, 12]]])
    
    In [11]: arr3d[1, 0]
    Out[11]: array([7, 8, 9])
    

    数组的切片索引

    In [12]: arr = np.arange(10)
    
    In [13]: arr[5: 8] = 64
    
    In [14]: arr
    Out[14]: array([ 0,  1,  2,  3,  4, 64, 64, 64,  8,  9])
    
    In [15]: arr[1: 6]
    Out[15]: array([ 1,  2,  3,  4, 64])
    
    In [16]: arr2d = np.array([[1, 2, 3], [4, 5, 6], [7, 8, 9]])
    
    In [17]: arr2d
    Out[17]:
    array([[1, 2, 3],
           [4, 5, 6],
           [7, 8, 9]])
    
    In [18]: arr2d[:2]
    Out[18]:
    array([[1, 2, 3],
           [4, 5, 6]])
    
    In [19]: arr2d[:2, 1:]
    Out[19]:
    array([[2, 3],
           [5, 6]])
    
    In [20]: arr2d[1, :2]
    Out[20]: array([4, 5])
    
    In [21]: arr2d[:2, 2]
    Out[21]: array([3, 6])
    
    In [22]: arr2d[:, :1]
    Out[22]:
    array([[1],
           [4],
           [7]])
    
    In [23]: arr2d[:2, 1:] = 0
    
    In [24]: arr2d
    Out[24]:
    array([[1, 0, 0],
           [4, 0, 0],
           [7, 8, 9]])
    

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