Swift 5.x 常用高阶函数

1. map 对于原始集合里的每一个元素, 以一个变换后的元素替换之形成一个新的集合

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• 1.1 flatmap 对于元素是集合的集合, 可以得到单级的集合
  

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let results = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
let allResults = results.flatMap{ $0.map{ $0 * 10 } }
let passMarks = results.flatMap{ $0.filter{ $0 > 5 } }

print(allResults)
print(passMarks)

输出结果:

[10, 20, 30, 40, 50, 60, 70, 80, 90]
[6, 7, 8, 9] 

• 1.2 compactMap 过滤空值
  

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let keys: [String?] = ["Zhangsan", nil, "Lisi", nil, "Wawngwu"]
let validNames = keys.compactMap{ $0 }
print(validNames)

let counts = keys.compactMap { $0?.count }
print(counts)

输出结果:

["Zhangsan", "Lisi", "Wawngwu"]
[8, 4, 7]

2. filter对于原始集合里的每一个元素, 通过判定来将其丢弃或者放进新集合

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let numbers: [Int] = [10, 20, 30, 40, 50, 60, 70, 80, 90]
print(numbers.filter{ $0 > 50})

输出结果:

[60, 70, 80, 90]

3. reduce 对于原始集合里的每一个元素, 作用与当前累积的结果上

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let numbers: [Int] = [1, 2, 3, 4, 5, 10]
print(numbers.reduce(0) { $0 + $1 })

输出结果:

25

注: reduce函数的第一个参数是一个初始值