美文网首页
70. Climbing Stairs

70. Climbing Stairs

作者: liuhaohaohao | 来源:发表于2018-04-24 15:03 被阅读0次

    You are climbing a stair case. It takes n steps to reach to the top.

    Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

    Note: Given n will be a positive integer.

    Example 1:
    
    Input: 2
    Output: 2
    Explanation: There are two ways to climb to the top.
    1. 1 step + 1 step
    2. 2 steps
    Example 2:
    
    Input: 3
    Output: 3
    Explanation: There are three ways to climb to the top.
    1. 1 step + 1 step + 1 step
    2. 1 step + 2 steps
    3. 2 steps + 1 step
    

    Solution

    class Solution {
        public int climbStairs(int n) {
            //f(n) = f(n-1) + f(n-2)
            if (n == 1 || n == 2)   {return n;}
            int[] map = new int[n];
            map[0] = 1;
            map[1] = 2;
            for (int i = 2; i < n; i++){
                map[i] = map[i-1] + map[i-2];
            }
            return map[n-1];
        }
    }
    

    相关文章

      网友评论

          本文标题:70. Climbing Stairs

          本文链接:https://www.haomeiwen.com/subject/opdjlftx.html