js截取url地址中的字符串参数方法
作者:
BugMyGod | 来源:发表于
2018-12-06 15:47 被阅读0次
eg:
http://localhost:63342/appwork/detail/detail.html?classId=xc56719940694a7c82948895de87801b&isShow=true
function GetRequest() {
var url = decodeURI(location.search); //获取url中"?"符后的字串
var theRequest = new Object();
if (url.indexOf("?") != -1) {
var str = url.substr(1);
strs = str.split("&");
for ( var i = 0; i < strs.length; i++) {
theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]);
}
}
return theRequest;
}
var Request=undefined;
Request=GetRequest();
var classId = Request["classId"];
var isShow = Request["isShow"];
本文标题:js截取url地址中的字符串参数方法
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