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LeetCode 1051. Height Checker (E

LeetCode 1051. Height Checker (E

作者: LiNGYu_NiverSe | 来源:发表于2020-11-11 01:07 被阅读0次

    Students are asked to stand in non-decreasing order of heights for an annual photo.

    Return the minimum number of students that must move in order for all students to be standing in non-decreasing order of height.

    Notice that when a group of students is selected they can reorder in any possible way between themselves and the non selected students remain on their seats.

    Example 1:
    Input: heights = [1,1,4,2,1,3]
    Output: 3
    Explanation:
    Current array : [1,1,4,2,1,3]
    Target array : [1,1,1,2,3,4]
    On index 2 (0-based) we have 4 vs 1 so we have to move this student.
    On index 4 (0-based) we have 1 vs 3 so we have to move this student.
    On index 5 (0-based) we have 3 vs 4 so we have to move this student.

    Example 2:
    Input: heights = [5,1,2,3,4]
    Output: 5

    Example 3:
    Input: heights = [1,2,3,4,5]
    Output: 0

    Constraints:
    1 <= heights.length <= 100
    1 <= heights[i] <= 100

    Solution:

    class Solution:
        def heightChecker(self, heights: List[int]) -> int:
            return sum(a != b for a, b in zip(heights, sorted(heights)))
    

    Explanation
    We can build a new sorted array and count the difference between two arrays by element-wise.

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