需求:对原始数据,当站点名称相同时,把相同名称的重新组合成数组
相关代码
var arr = res.msgs
var obj = {}
$.each(arr, function (key, val) {
var objArray = obj[val.factory_name] || []
objArray.push(val)
obj[val.factory_name] = objArray
})
$scope.homeSen = obj
console.log($scope.homeSen)
![](https://img.haomeiwen.com/i15149718/400208807c907d10.png)
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