滴滴校招-寻找丑数-c++

#include <iostream>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <map>
#include <string>
#include <vector>
#include <set>
#include <queue>
#include <deque>
#include <stack>
#include <algorithm>
#include <unordered_map>
using namespace std;
/*解题思路：
* http://blog.csdn.net/coder_xia/article/details/6707600 */
int Min(int a, int b, int c)     
{     
    int temp = (a < b ? a : b);     
    return (temp < c ? temp : c);     
}     
int FindUgly(int n) //  
{     
    int* ugly = new int[n];     
    ugly[0] = 1;     
    int index2 = 0;     
    int index3 = 0;     
    int index5 = 0;     
    int index = 1;     
    while (index < n)     
    {     
        int val = Min(ugly[index2]*2, ugly[index3]*3, ugly[index5]*5); //竞争产生下一个丑数     
        if (val == ugly[index2]*2) //将产生这个丑数的index*向后挪一位；    
            ++index2;     
        if (val == ugly[index3]*3)   //这里不能用elseif，因为可能有两个最小值，这时都要挪动；  
            ++index3;     
        if (val == ugly[index5]*5)     
            ++index5;     
        ugly[index++] = val;     
    }     

    int result = ugly[n-1];     
    delete[] ugly;     
    return result;     
}     
int main()     
{     
    int num;  
    cin >> num;  
    cout << FindUgly(num) << endl;  
    return 0;     
}  

面试题之丑数的C++实现求解（孤陋寡闻了，才知道丑数这么high的东东）