Huffman

作者: 滑二稽 | 来源:发表于2017-06-11 16:02 被阅读6次
    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    #define MAXN 100
    #define inf 1000.0
    
    typedef struct HtNode{
        double weight;
        int parent, lchild, rchild;
    };
    
    typedef struct HtTree{
        HtNode* ht;
        int root;
    };
    
    typedef HtTree* PHtTree;
    
    PHtTree Huffman(double* w, int n){
        PHtTree pht;
        int i, j, p1, p2;
        double min1, min2;
        if(n <= 1)  return pht; //
    
        pht = (PHtTree)malloc(sizeof(HtTree));
        pht -> ht = (HtNode*)malloc(sizeof(HtNode)*(2*n-1));
    
        for(i = 0; i < 2*n-1; i++){
            (pht->ht[i]).parent = -1;
            (pht->ht[i]).lchild = -1;
            (pht->ht[i]).rchild = -1;
            if(i < n)  (pht->ht[i]).weight = w[i];
            else (pht->ht[i]).weight = inf;
        }
    
        for(i = 0; i < n-1; i++){
    
            p1 = p2 = -1;
            min1 = min2 = inf;
            for(j = 0; j < n+i; j++)
                if((pht->ht[j]).parent == -1)
                if((pht->ht[j]).weight < min1){
                    min2 = min1;
                    min1 = (pht->ht[j]).weight;
                    p2 = p1;
                    p1 = j;
                }
                else if((pht->ht[j]).weight < min2){
                    min2 = (pht->ht[j]).weight;
                    p2 = j;
                }
    
            pht->ht[p1].parent = n+i;
            pht->ht[p2].parent = n+i;
            pht->ht[n+i].lchild = p1;
            pht->ht[n+i].rchild = p2;
            pht->ht[n+i].weight = min1+min2;
        }
    
        pht->root = 2*n-1;
        return pht;
    }
    
    void HuffmanCode(int i, PHtTree pht){
        int n = MAXN;
        int k, f;
        char c[MAXN] = {'\0'};
        int start = 0;
        for(k = i, f = pht->ht[i].parent; f != -1; k = f, f = pht->ht[f].parent){
            if(pht->ht[f].lchild == k)
                c[start] = '0';
            else
                c[start] = '1';
            start++;
        }
        strrev(c);
        printf("%d,\t%s\n", i, c);
    }
    
    int main(){
        int n = 8;
        double w[8] = {5, 29, 7, 8, 14, 23, 3, 11};
    
        PHtTree ppht;
    
        ppht = Huffman(w, n);
    
        for(int i = 0; i < 2*n - 1; i++)
            printf("%d,%d,%d,%d\n", i, ppht->ht[i].parent, ppht->ht[i].lchild, ppht->ht[i].rchild);
    
        printf("\n\n");
    
        for(int i = 0; i < n; i++)
            HuffmanCode(i, ppht);
    
        return 0;
    }
    
    

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