EntitlementTransaction的结构:
@Entity
@Table(name = EntitlementTransactionConstant.TABLE_ENTITLEMENT_TRANSACTION)
public class EntitlementTransaction implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(generator = "system-uuid")
@Column(name = EntitlementTransactionConstant.GUID )
private String guid;
@Column(name = EntitlementTransactionConstant.TRANSACTIONID,nullable = false)
private String transactionID;
@Column(name = EntitlementTransactionConstant.ENTITLEMENTNAME)
private String entitlementName;
@Column(name = EntitlementTransactionConstant.TYPE)
private String type;
@Column(name = EntitlementTransactionConstant.TENANTID)
private long tenantID;
@Column(name = EntitlementTransactionConstant.CUSTOMER)
private String customer;
@Column(name = EntitlementTransactionConstant.STORAGE)
private long storage;
@Column(name = EntitlementTransactionConstant.CPUCORE)
private long cpuCore;
@Column(name = EntitlementTransactionConstant.USERCOUNT)
private long userCount;
@Column(name = EntitlementTransactionConstant.STATUS)
private String status;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = EntitlementTransactionConstant.ENTITLEMENTID)
private EntitlementMaster entitlementMaster ;
@Entity
@Table(name = EntitlementMasterConstant.TABLE_Master_Constant)
public class EntitlementMaster implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(generator = "system-uuid")
@Column(name = EntitlementMasterConstant.GUID)
private String guid;
@Column(name = EntitlementMasterConstant.ENTITLEMENTNAME)
private String entitlementName;
@Column(name = EntitlementMasterConstant.ENTITLEMENTGUID)
private String entitlementID;
@Column(name = EntitlementMasterConstant.TYPE)
private String type;
@Column(name = EntitlementMasterConstant.TENANTID)
private long tenantID;
@Column(name = EntitlementMasterConstant.CUSTOMER)
private String customer;
@Column(name = EntitlementMasterConstant.STORAGE)
private long storage;
@Column(name = EntitlementMasterConstant.CPUCORE)
private long cpuCore;
@Column(name = EntitlementMasterConstant.USERCOUNT)
private long userCount;
@Column(name = EntitlementMasterConstant.OPERANT)
private String Operant;
@OneToMany(mappedBy = "entitlementMaster", fetch = FetchType.LAZY,cascade = CascadeType.ALL)
private Set<EntitlementTransaction> entitlementTransaction = new HashSet<>();
EntitleMaster的结构:
@Entity
@Table(name = EntitlementMasterConstant.TABLE_Master_Constant)
public class EntitlementMaster implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(generator = "system-uuid")
@Column(name = EntitlementMasterConstant.GUID)
private String guid;
@Column(name = EntitlementMasterConstant.ENTITLEMENTNAME)
private String entitlementName;
@Column(name = EntitlementMasterConstant.ENTITLEMENTGUID)
private String entitlementID;
@Column(name = EntitlementMasterConstant.TYPE)
private String type;
@Column(name = EntitlementMasterConstant.TENANTID)
private long tenantID;
@Column(name = EntitlementMasterConstant.CUSTOMER)
private String customer;
@Column(name = EntitlementMasterConstant.STORAGE)
private long storage;
@Column(name = EntitlementMasterConstant.CPUCORE)
private long cpuCore;
@Column(name = EntitlementMasterConstant.USERCOUNT)
private long userCount;
@Column(name = EntitlementMasterConstant.OPERANT)
private String Operant;
@OneToMany(mappedBy = "entitlementMaster", fetch = FetchType.LAZY,cascade = CascadeType.ALL)
private Set<EntitlementTransaction> entitlementTransaction = new HashSet<>();
这两张表通过EntitlementID字段来维持了双向映射的关系,在通过JPA对EntitlementTransaction表进行findALL()操作时,会因为这种双向映射关系导致反复查询同一条数据的情况,先来看数据库中的数据:
数据库中的数据而查询出来的数据却是这样的:
查询出的数据这个时候的Service层的代码是这样的:
@Autowired
EntitlementTransactionRepository entitlementTransactionRepository;
@Override
public List<EntitlementTransaction> getAll(){
return entitlementTransactionRepository.findAll();
}
如何解决这个问题呢?
首先新建EntitlementTransactionDtoNew类:
public class EntitlementTransactionDtoNew
{
private String guid;
private String entitlementID;
private String transactionID;
private String entitlementName;
private String type;
private long tenantID;
private String customer;
private long storage;
private long cpuCore;
private long userCount;
private String status;
getter and setter......
}
改写Service中的查询代码:
@Override
public List<EntitlementTransactionDtoNew> getAll(){
List<EntitlementTransactionDtoNew> entitlementTransactionDtoNews = new ArrayList<>();
for(EntitlementTransaction entitlementTransaction : entitlementTransactionRepository.findAll()){
EntitlementTransactionDtoNew entitlementTransactionDto = new EntitlementTransactionDtoNew();
entitlementTransactionDto.setGuid(entitlementTransaction.getGuid());
entitlementTransactionDto.setEntitlementID(entitlementTransaction.getEntitlementMaster().getEntitlementID());
entitlementTransactionDto.setTransactionID(entitlementTransaction.getTransactionID());
entitlementTransactionDto.setEntitlementName(entitlementTransaction.getEntitlementName());
entitlementTransactionDto.setType(entitlementTransaction.getType());
entitlementTransactionDto.setTenantID(entitlementTransaction.getTenantID());
entitlementTransactionDto.setCustomer(entitlementTransaction.getCustomer());
entitlementTransactionDto.setStorage(entitlementTransaction.getStorage());
entitlementTransactionDto.setCpuCore(entitlementTransaction.getCpuCore());
entitlementTransactionDto.setUserCount(entitlementTransaction.getUserCount());
entitlementTransactionDto.setStatus(entitlementTransaction.getStatus());
entitlementTransactionDtoNews.add(entitlementTransactionDto);
}
return entitlementTransactionDtoNews;
}
通过这样的方式就可以打破双向映射导致的反复查询,于是我们得到如下的正确的findAll结果如图:
正确结果这个问题是由JPA导致的,在同事的帮助下用这样的方式解决了该问题,希望JPA以后能够修复这个BUG。
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