swagger里面根据yml生成代码
作者:
刘书生 | 来源:发表于
2019-03-29 18:10 被阅读0次 <plugin>
<groupId>io.swagger</groupId>
<artifactId>swagger-codegen-maven-plugin</artifactId>
<version>2.3.1</version>
<executions>
<execution>
<phase>generate-sources</phase>
<goals>
<goal>generate</goal>
</goals>
<configuration>
<inputSpec>${basedir}/target/swagger/swagger.yaml</inputSpec>
<language>java</language>
<modelPackage>net.bingosoft.apigw.cp.model</modelPackage>
<apiPackage>net.bingosoft.apigw.cp.internal.api</apiPackage>
<invokerPackage>net.bingosoft.apigw.cp.internal</invokerPackage>
<generateApis>true</generateApis>
<withXml>false</withXml>
<generateApiTests>false</generateApiTests>
<generateApiDocumentation>false</generateApiDocumentation>
<generateSupportingFiles>true</generateSupportingFiles>
<addCompileSourceRoot>false</addCompileSourceRoot>
<templateDirectory>codegen/template/java</templateDirectory>
<configOptions>
<dateLibrary>legacy</dateLibrary>
<java8>true</java8>
</configOptions>
</configuration>
</execution>
</executions>
</plugin>
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