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swagger里面根据yml生成代码

swagger里面根据yml生成代码

作者: 刘书生 | 来源:发表于2019-03-29 18:10 被阅读0次
 <plugin>
                <groupId>io.swagger</groupId>
                <artifactId>swagger-codegen-maven-plugin</artifactId>
                <version>2.3.1</version>
                <executions>
                    <execution>
                        <phase>generate-sources</phase>
                        <goals>
                            <goal>generate</goal>
                        </goals>
                        <configuration>
                            <inputSpec>${basedir}/target/swagger/swagger.yaml</inputSpec>
                            <language>java</language>
                            <modelPackage>net.bingosoft.apigw.cp.model</modelPackage>
                            <apiPackage>net.bingosoft.apigw.cp.internal.api</apiPackage>
                            <invokerPackage>net.bingosoft.apigw.cp.internal</invokerPackage>
                            <generateApis>true</generateApis>
                            <withXml>false</withXml>
                            <generateApiTests>false</generateApiTests>
                            <generateApiDocumentation>false</generateApiDocumentation>
                            <generateSupportingFiles>true</generateSupportingFiles>
                            <addCompileSourceRoot>false</addCompileSourceRoot>
                            <templateDirectory>codegen/template/java</templateDirectory>
                            <configOptions>
                                <dateLibrary>legacy</dateLibrary>
                                <java8>true</java8>
                            </configOptions>
                        </configuration>
                    </execution>
                </executions>
            </plugin>

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