swagger根据代码生成yml
作者:
刘书生 | 来源:发表于
2019-03-29 18:00 被阅读0次 <plugin>
<groupId>com.github.kongchen</groupId>
<artifactId>swagger-maven-plugin</artifactId>
<version>3.1.7</version>
<executions>
<execution>
<phase>package</phase>
<goals>
<goal>generate</goal>
</goals>
</execution>
</executions>
<configuration>
<apiSources>
<apiSource>
<locations>cn.wgd.zmx.controller</locations> //你要生成api的路径
<info>
<title>志愿填报API</title>
<version>0.0.1-SNAPSHOT</version>
</info>
<schemes>http</schemes>
<host>localhost</host>
<outputFormats>yaml</outputFormats>
<swaggerApiReader>com.github.kongchen.swagger.docgen.reader.SpringMvcApiReader
</swaggerApiReader>
<swaggerDirectory>${basedir}/target/swagger</swaggerDirectory> //生成后存放的位置
</apiSource>
</apiSources>
</configuration>
</plugin>
本文标题:swagger根据代码生成yml
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