美文网首页
Decode Ways

Decode Ways

作者: 极速魔法 | 来源:发表于2017-07-21 11:31 被阅读7次

//91

A message containing letters from A-Z is being encoded to numbers using the following mapping:

'A' -> 1
'B' -> 2
...
'Z' -> 26
Given an encoded message containing digits, determine the total number of ways to decode it.

For example,
Given encoded message "12", it could be decoded as "AB" (1 2) or "L" (12).

The number of ways decoding "12" is 2.

#include <iostream>
#include <vector>


using namespace std;
//similar to climbing stairs,dp[i-1] check s[i]!=0
//dp[i-2] check s[i-1]s[i] range 1-26
class Solution {
private:
    int validNum(char two,char one){
        //deal with input "01"
        if(two=='0'){
            return 0;
        }
        if(one=='0'){
            if(two>='3' || two=='0'){
                return 0;
            } else{
                return 1;
            }
        } else{
            if(two=='1' || (two=='2' && one<='6')){
                return 2;
            } else{
                return 1;
            }
        }

    }
public:
    int numDecodings(string s) {
        int size=s.size();
        if(size==0){
            return 0;
        }
        vector<int> dp(size,0);
        //init
        if(s[0] !='0'){
            dp[0]=1;
        }
        
       dp[1]=validNum(s[0],s[1]);
        
        for(int i=2;i<size;i++){
            if(s[i]!='0'){
                dp[i]+=dp[i-1];
            } 

            if((s[i-1]=='1' && s[i]>='0') || (s[i-1]=='2' && s[i]<='6')){
                dp[i]+=dp[i-2];
            }
        }

        return dp[size-1];
    }
};

int main(){
    string s="110";
    cout<<Solution().numDecodings(s);
    return 0;
}

相关文章

网友评论

      本文标题:Decode Ways

      本文链接:https://www.haomeiwen.com/subject/qioskxtx.html