题目描述
Given a non-negative integer numRows, generate the first numRows of Pascal's triangle.
In Pascal's triangle, each number is the sum of the two numbers directly above it.
Example:
Input: 5
Output:
[
[1],
[1,1],
[1,2,1],
[1,3,3,1],
[1,4,6,4,1]
]
题目思路
代码 C++
- 思路一、
class Solution {
public:
vector<vector<int>> generate(int numRows) {
vector<vector<int>> result;
vector<int> a;
vector<int> b;
for(int i=1; i <= numRows; i++){
if(i == 1){
a.push_back(1);
result.push_back(a);
}
else if(i == 2){
b.push_back(1);
b.push_back(1);
result.push_back(b);
}
else{
a.clear();
a.push_back(1);
for(int i=0; i < b.size()-1; i++){
a.push_back(b[i]+b[i+1]);
}
a.push_back(1);
result.push_back(a);
b = a;
}
}
return result;
}
};

- 思路二、
class Solution {
public:
vector<vector<int>> generate(int numRows) {
vector<vector<int>> result(numRows);
for(int i=0; i < numRows; i++){
result[i].resize(i+1);
result[i][0] = result[i][i] = 1;
for(int j=1; j < i; j++){
result[i][j] = result[i-1][j-1] + result[i-1][j];
}
}
return result;
}
};
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