原文链接:https://www.thinbug.com/q/46849286
通过es6的map
const arr1 = [
{ id: "abdc4051", date: "2017-01-24" },
{ id: "abdc4052", date: "2017-01-22" },
{ id: "abdc4053", date: "2017-01-22" }
];
const arr2 = [
{ nameId: "abdc4051", name: "ab" },
{ nameId: "abdc4052", name: "abc" }
];
const map = new Map();
arr1.forEach(item => map.set(item.id, item));
arr2.forEach(item => map.set(item.nameId, {...map.get(item.nameId), ...item}));
const mergedArr = Array.from(map.values());
通过find 一步到位
let arr1 = [
{ id: "abdc4051", date: "2017-01-24" },
{ id: "abdc4052", date: "2017-01-22" }
];
let arr2 = [
{ id: "abdc4051", name: "ab" },
{ id: "abdc4052", name: "abc" }
];
const mergeById = (a1, a2) =>
a1.map(itm => ({
...a2.find((item) => (item.id === itm.id) && item),
...itm
}));
console.log(mergeById(arr1, arr2));
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