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多人投票,对票数进行统计,同时支持去掉最高和最低

多人投票,对票数进行统计,同时支持去掉最高和最低

作者: 求索_700e | 来源:发表于2019-11-30 10:33 被阅读0次

    import numpy as np

    fangzi=np.array([2,1,3,1,6,1,1,1])

    tianhong=np.array([1,9,5,3,8,9,10,3])

    kekong=np.array([3,4,2,2,10,3,5,9])

    duxu=np.array([4,3,1,5,7,6,3,5])

    xiaon=np.array([5,6,8,6,4,7,6,8])

    dongy=np.array([6,2,4,4,5,5,2,4])

    shij=np.array([7,5,13,7,2,4,4,10])

    wangx=np.array([8,8,10,13,9,11,13,13])

    zhangf=np.array([9,10,6,8,13,2,9,2])

    suh=np.array([10,12,7,11,3,10,8,6])

    dengs=np.array([11,11,9,10,12,8,11,12])

    zhangc=np.array([12,7,12,9,11,12,12,7])

    xiaom=np.array([13,13,11,12,1,13,7,11])

    table=[fangzifan, tianhongliang,kekongde,duxuan,xiaonengqi,dongyuanfa,shijinjin,wangxiaopeng,zhangfajun,suhuashan,dengshoucheng,zhangcunji,xiaomin]

    name=["fangzi", "tianh","kek","dux","xiaon",

          "dongy","shij","wangx","zhangf","suh","dengs","zhangc","xiaom"]

    k=0

    for i in table:

        s=np.sort(i)

        #print(name[k]+" = ", np.mean(s[1:-1]))   

        #k+=1 

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