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python 一阶段测试答案

python 一阶段测试答案

作者: python76 | 来源:发表于2019-10-01 21:08 被阅读0次

    # title1

    fruit ="apples"

    n =3

    phraes ="i want"

    print(phraes, n, fruit)

    # title2

    """

    如何命名: 数字,字母,下滑线组成,且不能以数字开头_apple = 3  true

    3apple = 3  false

    greenApple = 3 true

    apple = 3 true

    苹果= 3 false

    apple3 = 3 true

    """

    # title3

    """

    字符串 string  "我是一个字符串"

    列表 list      ["我", "是", "一个", "列表"]

    整型int      num = 3

    布尔bool      a = True

    字典dict

    元组tuple

    集合set

    """

    # title4

    # int_num = input("你输入的整数是什么")

    # shang = int(int_num)//3

    # yushu = int(int_num)%3

    # print("商是{}".format(shang))

    # print("余数是{}".format(yushu))

    # title5

              #条件1  条件2

    choose1 = [True,True]

    choose2 = [True,False]

    choose3 = [False,True]

    choose4 = [False,False]

    res1 =not choose1[0]and choose1[1]

    res2 =not choose2[0]and choose2[1]

    res3 =not choose3[0]and choose3[1]

    res4 =not choose4[0]and choose4[1]

    print(res1, res2, res3, res4)

    # title6

    x = ["how","hello, world","hello"]

    x.append("hello")# ["how", "hello, world", "hello", "hello"]

    x[2] ="world" # ["how", "hello, world", "world", "hello"]

    x.remove("hello")# ["how", "hello, world", "world"]

    print(x[2])

    # tile7

    print(len(x))

    # title8 pass

    # 闰年:能被400整除,或者能被4整除且不能100整除

    # 如果这个年份能被100整除的话 :让他去判断能不能被400整除

    # 如果这个年份都不能被100整除,直接判断被整除4

    while True:

    year =input("请输入你所需要查询的年份,输入exit退出程序")

    if year =="exit":

    print("退出程序")

    break

        if int(year) %100 ==0:

    if int(year) %400 ==0:

    print("{}是闰年".format(year))

    continue

            print("{}是平年".format(year))

    continue

        if int(year) %4 ==0:

    print("{}是闰年".format(year))

    continue

        print("{}是平年".format(year))

    continue

    # title9

    a ="ab2b3n5n2n67mm4n2"

    lst = []

    for charin a:

    lst.append(char)

    print(lst.count("n"))

    # title10

    count_n =0

    for charin a:

    if char =="n":

    count_n = count_n +1

    print(count_n)

    # title11

    print(a.count("n"))

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