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算法(06)跳表

算法(06)跳表

作者: 迷心迷 | 来源:发表于2020-02-09 19:48 被阅读0次
    @SuppressWarnings("unchecked")
    public class SkipList<K, V> {
        private static final int MAX_LEVEL = 32;
        private static final double P = 0.25;
        private int size;
        private Comparator<K> comparator;
        /**
         * 有效层数
         */
        private int level;
        /**
         * 不存放任何K-V
         */
        private Node<K, V> first;
        
        public SkipList(Comparator<K> comparator) {
            this.comparator = comparator;
            first = new Node<>(null, null, MAX_LEVEL);
        }
        
        public SkipList() {
            this(null);
        }
        
        public int size() {
            return size;
        }
        
        public boolean isEmpty() {
            return size == 0;
        }
        
        public V get(K key) {
            keyCheck(key);
            
            // first.nexts[3] == 21节点
            // first.nexts[2] == 9节点
            // first.nexts[1] == 6节点
            // first.nexts[0] == 3节点
            
            // key = 30
            // level = 4
            
            Node<K, V> node = first;
            for (int i = level - 1; i >= 0; i--) {
                int cmp = -1;
                while (node.nexts[i] != null 
                        && (cmp = compare(key, node.nexts[i].key)) > 0) {
                    node = node.nexts[i];
                }
                // node.nexts[i].key >= key
                if (cmp == 0) return node.nexts[i].value;
            }
            return null;
        }
        
        public V put(K key, V value) {
            keyCheck(key);
            
            Node<K, V> node = first;
            Node<K, V>[] prevs = new Node[level];
            for (int i = level - 1; i >= 0; i--) {
                int cmp = -1;
                while (node.nexts[i] != null 
                        && (cmp = compare(key, node.nexts[i].key)) > 0) {
                    node = node.nexts[i];
                }
                if (cmp == 0) { // 节点是存在的
                    V oldV = node.nexts[i].value;
                    node.nexts[i].value = value;
                    return oldV;
                }
                prevs[i] = node;
            }
            
            // 新节点的层数
            int newLevel = randomLevel();
            // 添加新节点
            Node<K, V> newNode = new Node<>(key, value, newLevel);
            // 设置前驱和后继
            for (int i = 0; i < newLevel; i++) {
                if (i >= level) {
                    first.nexts[i] = newNode;
                } else {
                    newNode.nexts[i] = prevs[i].nexts[i];
                    prevs[i].nexts[i] = newNode;
                }
            }
            
            // 节点数量增加
            size++;
            
            // 计算跳表的最终层数
            level = Math.max(level, newLevel);
            
            return null;
        }
        
        public V remove(K key) {
            keyCheck(key);
            
            Node<K, V> node = first;
            Node<K, V>[] prevs = new Node[level];
            boolean exist = false;
            for (int i = level - 1; i >= 0; i--) {
                int cmp = -1;
                while (node.nexts[i] != null 
                        && (cmp = compare(key, node.nexts[i].key)) > 0) {
                    node = node.nexts[i];
                }
                prevs[i] = node;
                if (cmp == 0) exist = true;
            }
            if (!exist) return null;
            
            // 需要被删除的节点
            Node<K, V> removedNode = node.nexts[0];
            
            // 数量减少
            size--;
            
            // 设置后继
            for (int i = 0; i < removedNode.nexts.length; i++) {
                prevs[i].nexts[i] = removedNode.nexts[i];
            }
            
            // 更新跳表的层数
            int newLevel = level;
            while (--newLevel >= 0 && first.nexts[newLevel] == null) {
                level = newLevel;
            }
            
            return removedNode.value;
        }
        
        private int randomLevel() {
            int level = 1;
            while (Math.random() < P && level < MAX_LEVEL) {
                level++;
            }
            return level;
        }
        
        private void keyCheck(K key) {
            if (key == null) {
                throw new IllegalArgumentException("key must not be null.");
            }
        }
        
        private int compare(K k1, K k2) {
            return comparator != null 
                    ? comparator.compare(k1, k2)
                    : ((Comparable<K>)k1).compareTo(k2);
        }
        
        private static class Node<K, V> {
            K key;
            V value;
            Node<K, V>[] nexts;
    //      Node<K, V> right;
    //      Node<K, V> down;
    //      Node<K, V> top;
    //      Node<K, V> left;
            public Node(K key, V value, int level) {
                this.key = key;
                this.value = value;
                nexts = new Node[level];
            }
            @Override
            public String toString() {
                return key + ":" + value + "_" + nexts.length;
            }
        }
        
        @Override
        public String toString() {
            StringBuilder sb = new StringBuilder();
            sb.append("一共" + level + "层").append("\n");
            for (int i = level - 1; i >= 0; i--) {
                Node<K, V> node = first;
                while (node.nexts[i] != null) {
                    sb.append(node.nexts[i]);
                    sb.append(" ");
                    node = node.nexts[i];
                }
                sb.append("\n");
            }
            return sb.toString();
        }
    }
    
    

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