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2019-08-09:中位数计算

2019-08-09:中位数计算

作者: AI_Finance | 来源:发表于2019-08-09 23:02 被阅读0次
    select "首剂抗生素中位数" as "指标名称", first_time as "数值" from 
    (
        select  @ID:=@ID+1 AS ID, first_time from 
    (
        select detail.uuid, TIMESTAMPDIFF(HOUR, csa.admission_date, if(antibiotic_execute_date is not null, antibiotic_execute_date, antibiotic_create_date)) as first_time  from cap_statistics_antibiotic as csa
        join yd_patient_11_basic_info as detail
        on detail.uuid=csa.uuid
    --  where { discharge_date BETWEEN [ startTime2 ]} AND {[ endTime2 ]}
    --  AND { inpatient_department = [ inpatient_department ]}  
    --  AND { disease_name = [disease_class_name ]}  
    --  AND { diagnosis_category = [ diagnose_class_name ]}
    ) as a, (SELECT @ID:=0) as b
    order by first_time
    ) t where id = ((@ID+1) div 2)
    

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