- 用*号输出字母c的图案
#用*号输出字母c的图案
spaceNum = [30, 25, 18, 15, 12, 10, 8, 6, 5, 4, 3, 3]
space = ' '
star = '*'
for i in range(1, len(spaceNum)):
print(spaceNum[i] * space, star)
spaceNum.reverse()
for i in range(1, len(spaceNum)):
print(spaceNum[i] * space, star)
建立了一个list,遍历list,将list元素作为空格,最后反向遍历再输出
- 第七题是特么什么玩意?直接pass
- 输出九九乘法表
'''输出九九乘法表'''
for i in range(1,10):
for j in range(1,i+1):
print(i,'x',j,'=',i*j,'\t',end='')
print()
输出结果:
D:\anaconda\python.exe D:/bilibili大学/python经典习题100道/习题9.py
1 x 1 = 1
2 x 1 = 2 2 x 2 = 4
3 x 1 = 3 3 x 2 = 6 3 x 3 = 9
4 x 1 = 4 4 x 2 = 8 4 x 3 = 12 4 x 4 = 16
5 x 1 = 5 5 x 2 = 10 5 x 3 = 15 5 x 4 = 20 5 x 5 = 25
6 x 1 = 6 6 x 2 = 12 6 x 3 = 18 6 x 4 = 24 6 x 5 = 30 6 x 6 = 36
7 x 1 = 7 7 x 2 = 14 7 x 3 = 21 7 x 4 = 28 7 x 5 = 35 7 x 6 = 42 7 x 7 = 49
8 x 1 = 8 8 x 2 = 16 8 x 3 = 24 8 x 4 = 32 8 x 5 = 40 8 x 6 = 48 8 x 7 = 56 8 x 8 = 64
9 x 1 = 9 9 x 2 = 18 9 x 3 = 27 9 x 4 = 36 9 x 5 = 45 9 x 6 = 54 9 x 7 = 63 9 x 8 = 72 9 x 9 = 81
Process finished with exit code 0
这个是不太难理解哦,其实可以更优化一点儿。
'''输出九九乘法表'''
for i in range(1,10):
for j in range(1,i+1):
print('{}x{}={}\t'.format(j,i,i*j),end='')
print()
输出结果:
D:\anaconda\python.exe D:/bilibili大学/python经典习题100道/习题9.py
1x1=1
1x2=2 2x2=4
1x3=3 2x3=6 3x3=9
1x4=4 2x4=8 3x4=12 4x4=16
1x5=5 2x5=10 3x5=15 4x5=20 5x5=25
1x6=6 2x6=12 3x6=18 4x6=24 5x6=30 6x6=36
1x7=7 2x7=14 3x7=21 4x7=28 5x7=35 6x7=42 7x7=49
1x8=8 2x8=16 3x8=24 4x8=32 5x8=40 6x8=48 7x8=56 8x8=64
1x9=9 2x9=18 3x9=27 4x9=36 5x9=45 6x9=54 7x9=63 8x9=72 9x9=81
Process finished with exit code 0
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