Leetcode-449Serialize and Deseri

449. Serialize and Deserialize BST

Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment.

Design an algorithm to serialize and deserialize a binary search tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary search tree can be serialized to a string and this string can be deserialized to the original tree structure.

The encoded string should be as compact as possible.

Note: Do not use class member/global/static variables to store states. Your serialize and deserialize algorithms should be stateless.

My Solution:

# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Codec:
    def serialize(self, root):
        """Encodes a tree to a single string.

        :type root: TreeNode
        :rtype: str
        """
        if not root:
            return ''
        str_list = []
        self.get_str(root, str_list)
        return '#'.join(str_list)

    def get_str(self, root, str_list):
        if not root:
            return
        str_list.append(str(root.val))
        self.get_str(root.left, str_list)
        self.get_str(root.right, str_list)

    def deserialize(self, data): # data = self.serialize(root)
        """Decodes your encoded data to tree.

        :type data: str
        :rtype: TreeNode
        """
        if data == '':
            return None
        value_list = data.split('#')
        root = TreeNode(int(value_list[0]))
        for value in value_list[1:]:
            self.insertBST(root, node=TreeNode(int(value)))
        return root

    def insertBST(self, root, node):
        if node.val < root.val:
            if root.left:
                return self.insertBST(root.left, node)
            else:
                root.left = node
        if node.val > root.val:
            if root.right:
                return self.insertBST(root.right, node)
            else:
                root.right = node
        return root
        

# Your Codec object will be instantiated and called as such:
# codec = Codec()
# codec.deserialize(codec.serialize(root))

Reference:

用deque代替List：

# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Codec:

    def serialize(self, root):
        vals = []

        def preOrder(node):
            if node:
                vals.append(node.val)
                preOrder(node.left)
                preOrder(node.right)

        preOrder(root)

        return ' '.join(map(str, vals))

    # O( N ) since each val run build once
    def deserialize(self, data):
        vals = collections.deque(int(val) for val in data.split())

        def build(minVal, maxVal):
            if vals and minVal < vals[0] < maxVal:
                val = vals.popleft()
                node = TreeNode(val)
                node.left = build(minVal, val)
                node.right = build(val, maxVal)
                return node

        return build(float('-infinity'), float('infinity'))



# Your Codec object will be instantiated and called as such:
# codec = Codec()
# codec.deserialize(codec.serialize(root))