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那些能提升开发速度的Bean操作

那些能提升开发速度的Bean操作

作者: 夜色001 | 来源:发表于2021-09-15 00:07 被阅读0次

    @Accessors(chain = true)

    @Data
    @Accessors(chain = true)
    public class TodayOutDepositVo {
    
        @ApiModelProperty(value = "入住订单id")
        @NotNull(groups = {UpdateGroup.class}, message = "入住订单id 不能为空")
        private Long id;
        @ApiModelProperty(value = "序号")
        private Integer i;
    
    TodayOutDepositVo vo = BeanUtil.copyProperties(roomOrder, TodayOutDepositVo.class);
                vo.setI(i).setLiveTime(DateFormatUtil.toFormat(roomOrder.getArrivalTime(), Pattern.PATTERN2))
                        .setLeaveTime(DateFormatUtil.toFormat(roomOrder.getDepartureTime(), Pattern.PATTERN2))
                        .setDepositPayWay(depositPayWay.getMsg()).setRoomFee(totalRoomFee.toString())
                        .setRoomPayWay(receivablePayWay.getMsg()).setRoomNum(room.getRoomNum())
                        .setDepositReturnWay(returnWayEnum == null ? "" : returnWayEnum.getMsg())
                        .setShouldReceiveReturn(returnFee.toString())
                        .setIsComeBack(roomOrder.getIsDepositBack() == null || !"1".equals(roomOrder.getIsDepositBack()) ? "未退" : "已退")
    

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