美文网首页
那些能提升开发速度的Bean操作

那些能提升开发速度的Bean操作

作者: 夜色001 | 来源:发表于2021-09-15 00:07 被阅读0次

@Accessors(chain = true)

@Data
@Accessors(chain = true)
public class TodayOutDepositVo {

    @ApiModelProperty(value = "入住订单id")
    @NotNull(groups = {UpdateGroup.class}, message = "入住订单id 不能为空")
    private Long id;
    @ApiModelProperty(value = "序号")
    private Integer i;
TodayOutDepositVo vo = BeanUtil.copyProperties(roomOrder, TodayOutDepositVo.class);
            vo.setI(i).setLiveTime(DateFormatUtil.toFormat(roomOrder.getArrivalTime(), Pattern.PATTERN2))
                    .setLeaveTime(DateFormatUtil.toFormat(roomOrder.getDepartureTime(), Pattern.PATTERN2))
                    .setDepositPayWay(depositPayWay.getMsg()).setRoomFee(totalRoomFee.toString())
                    .setRoomPayWay(receivablePayWay.getMsg()).setRoomNum(room.getRoomNum())
                    .setDepositReturnWay(returnWayEnum == null ? "" : returnWayEnum.getMsg())
                    .setShouldReceiveReturn(returnFee.toString())
                    .setIsComeBack(roomOrder.getIsDepositBack() == null || !"1".equals(roomOrder.getIsDepositBack()) ? "未退" : "已退")

相关文章

网友评论

      本文标题:那些能提升开发速度的Bean操作

      本文链接:https://www.haomeiwen.com/subject/rxtkgltx.html