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labelme批量处理图片

labelme批量处理图片

作者: 做只小考拉 | 来源:发表于2018-11-08 10:07 被阅读488次

    在此,对于labelme安装就不再赘述了,初学者可参考github地址https://github.com/wkentaro/labelme

    这里,我修改了一下json_to_dataset.py文件,就可以批量生成了,执行 python <文件夹名称>即可:

    import argparse
    import base64
    import json
    import os
    import os.path as osp
    import warnings
    
    import PIL.Image
    import yaml
    
    from labelme import utils
    
    
    def main():
        warnings.warn("This script is aimed to demonstrate how to convert the\n"
                      "JSON file to a single image dataset, and not to handle\n"
                      "multiple JSON files to generate a real-use dataset.")
    
        parser = argparse.ArgumentParser()
        parser.add_argument('json_file')
        parser.add_argument('-o', '--out', default=None)
        args = parser.parse_args()
    
        json_file = args.json_file
        
        list_file = os.listdir(json_file)
        
    #     if args.out is None:
    #         out_dir = osp.basename(json_file).replace('.', '_')
    #         out_dir = osp.join(osp.dirname(json_file), out_dir)
    #     else:
    #         out_dir = args.out
    #     if not osp.exists(out_dir):
    #         os.mkdir(out_dir)
            
        for i in range(0,len(list_file)):
            if args.out is None:
                out_dir = osp.basename(list_file[i]).replace('.', '_')
                out_dir = osp.join(osp.dirname(list_file[i]), out_dir)
            else:
                out_dir = args.out
            if not osp.exists(out_dir):
                os.mkdir(out_dir)
            
            path = os.path.join(json_file, list_file[i])
            data = json.load(open(path))
    
            if data['imageData']:
                imageData = data['imageData']
            else:
                imagePath = os.path.join(os.path.dirname(json_file), data['imagePath'])
                with open(imagePath, 'rb') as f:
                    imageData = f.read()
                    imageData = base64.b64encode(imageData).decode('utf-8')
            img = utils.img_b64_to_arr(imageData)
    
            label_name_to_value = {'_background_': 0}
            for shape in sorted(data['shapes'], key=lambda x: x['label']):
                label_name = shape['label']
                if label_name in label_name_to_value:
                    label_value = label_name_to_value[label_name]
                else:
                    label_value = len(label_name_to_value)
                    label_name_to_value[label_name] = label_value
            lbl = utils.shapes_to_label(img.shape, data['shapes'], label_name_to_value)
    
            label_names = [None] * (max(label_name_to_value.values()) + 1)
            for name, value in label_name_to_value.items():
                label_names[value] = name
            lbl_viz = utils.draw_label(lbl, img, label_names)
    
            PIL.Image.fromarray(img).save(osp.join(out_dir, 'img.png'))
            utils.lblsave(osp.join(out_dir, 'label.png'), lbl)
            PIL.Image.fromarray(lbl_viz).save(osp.join(out_dir, 'label_viz.png'))
    
            with open(osp.join(out_dir, 'label_names.txt'), 'w') as f:
                for lbl_name in label_names:
                    f.write(lbl_name + '\n')
    
            warnings.warn('info.yaml is being replaced by label_names.txt')
            info = dict(label_names=label_names)
            with open(osp.join(out_dir, 'info.yaml'), 'w') as f:
                yaml.safe_dump(info, f, default_flow_style=False)
    
            print('Saved to: %s' % out_dir)
    
    
    if __name__ == '__main__':
        main()
    

    如此处理完成之后,每一张图片都将生成一个以_json结尾的文件夹,其中对应5个文件。然而要取出所有图像的label.png文件每次一张一张图片的复制太过于繁琐,在此我们用代码去进行批量处理,将每一张图片的label.png复制到新的文件夹中。

    import cv2 as cv  
    import random  
    import glob  
    import os
    from PIL import Image
    import shutil
    
    def get_samples(foldername,savePath):
        print('savePath:',savePath)
        if os.path.exists(savePath) is False:
            os.makedirs(savePath)
       
        filenames = os.listdir(foldername)
                
        for filename in filenames:  
            full_path = os.path.join(foldername, filename)
            new_name = filename[:-5]+'.png'
            label_png = os.listdir(full_path)[2]
            #os.rename(os.path.join(filename, label_png),os.path.join(filename, name))
            shutil.copy(os.path.join(full_path, label_png), os.path.join(savePath, label_png))
            os.rename(os.path.join(savePath, label_png),os.path.join(savePath, new_name))
            #print(os.listdir(filename))
            
    savePath = 'E:\\label\\yejian\\'  
    get_samples('E:\\水尺2\\yejian',savePath )       
    

    本文为作者原创文章,转载请申明出处。

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