在此,对于labelme安装就不再赘述了,初学者可参考github地址https://github.com/wkentaro/labelme
这里,我修改了一下json_to_dataset.py文件,就可以批量生成了,执行 python <文件夹名称>即可:
import argparse
import base64
import json
import os
import os.path as osp
import warnings
import PIL.Image
import yaml
from labelme import utils
def main():
warnings.warn("This script is aimed to demonstrate how to convert the\n"
"JSON file to a single image dataset, and not to handle\n"
"multiple JSON files to generate a real-use dataset.")
parser = argparse.ArgumentParser()
parser.add_argument('json_file')
parser.add_argument('-o', '--out', default=None)
args = parser.parse_args()
json_file = args.json_file
list_file = os.listdir(json_file)
# if args.out is None:
# out_dir = osp.basename(json_file).replace('.', '_')
# out_dir = osp.join(osp.dirname(json_file), out_dir)
# else:
# out_dir = args.out
# if not osp.exists(out_dir):
# os.mkdir(out_dir)
for i in range(0,len(list_file)):
if args.out is None:
out_dir = osp.basename(list_file[i]).replace('.', '_')
out_dir = osp.join(osp.dirname(list_file[i]), out_dir)
else:
out_dir = args.out
if not osp.exists(out_dir):
os.mkdir(out_dir)
path = os.path.join(json_file, list_file[i])
data = json.load(open(path))
if data['imageData']:
imageData = data['imageData']
else:
imagePath = os.path.join(os.path.dirname(json_file), data['imagePath'])
with open(imagePath, 'rb') as f:
imageData = f.read()
imageData = base64.b64encode(imageData).decode('utf-8')
img = utils.img_b64_to_arr(imageData)
label_name_to_value = {'_background_': 0}
for shape in sorted(data['shapes'], key=lambda x: x['label']):
label_name = shape['label']
if label_name in label_name_to_value:
label_value = label_name_to_value[label_name]
else:
label_value = len(label_name_to_value)
label_name_to_value[label_name] = label_value
lbl = utils.shapes_to_label(img.shape, data['shapes'], label_name_to_value)
label_names = [None] * (max(label_name_to_value.values()) + 1)
for name, value in label_name_to_value.items():
label_names[value] = name
lbl_viz = utils.draw_label(lbl, img, label_names)
PIL.Image.fromarray(img).save(osp.join(out_dir, 'img.png'))
utils.lblsave(osp.join(out_dir, 'label.png'), lbl)
PIL.Image.fromarray(lbl_viz).save(osp.join(out_dir, 'label_viz.png'))
with open(osp.join(out_dir, 'label_names.txt'), 'w') as f:
for lbl_name in label_names:
f.write(lbl_name + '\n')
warnings.warn('info.yaml is being replaced by label_names.txt')
info = dict(label_names=label_names)
with open(osp.join(out_dir, 'info.yaml'), 'w') as f:
yaml.safe_dump(info, f, default_flow_style=False)
print('Saved to: %s' % out_dir)
if __name__ == '__main__':
main()
如此处理完成之后,每一张图片都将生成一个以_json结尾的文件夹,其中对应5个文件。然而要取出所有图像的label.png文件每次一张一张图片的复制太过于繁琐,在此我们用代码去进行批量处理,将每一张图片的label.png复制到新的文件夹中。
import cv2 as cv
import random
import glob
import os
from PIL import Image
import shutil
def get_samples(foldername,savePath):
print('savePath:',savePath)
if os.path.exists(savePath) is False:
os.makedirs(savePath)
filenames = os.listdir(foldername)
for filename in filenames:
full_path = os.path.join(foldername, filename)
new_name = filename[:-5]+'.png'
label_png = os.listdir(full_path)[2]
#os.rename(os.path.join(filename, label_png),os.path.join(filename, name))
shutil.copy(os.path.join(full_path, label_png), os.path.join(savePath, label_png))
os.rename(os.path.join(savePath, label_png),os.path.join(savePath, new_name))
#print(os.listdir(filename))
savePath = 'E:\\label\\yejian\\'
get_samples('E:\\水尺2\\yejian',savePath )
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