ios如何获取数组中的最大值和最小值

第一种：快速求和

    NSArray * array = @[@"20",@"80",@"99",@"86",@"68",@"39",@"69",@"23",@"79",@"97"];
    
    float sum = [[array valueForKeyPath:@"@sum.floatValue"] floatValue];
    
    float avg = [[array valueForKeyPath:@"@avg.floatValue"] floatValue];
    
    float max =[[array valueForKeyPath:@"@max.floatValue"] floatValue];
    
    float min =[[array valueForKeyPath:@"@min.floatValue"] floatValue];   

第二种：循环遍历 拿到自己想要的索引下标

 NSArray * array = @[@"20",@"80",@"99",@"86",@"68",@"39",@"69",@"23",@"79",@"97"];
    int max_number = 0;
    int max_index = 0;
    
    int min_number = 0;
    int min_index = 0;
    
    int all = 0;
    float mid = 0;
    
    for (int i = 0; i<array.count; i++) {
        //取最大值和最大值的对应下标
        int a = [array[i] integerValue];
        if (a > max_number) {
            max_index = i;
        }
        max_number = a>max_number?a:max_number;
        //取最小值和最小值的对应下标

        int b = [array[i] integerValue];
        if (b<min_number) {
            min_index = i;
        }
        min_number = b<min_number?b:min_number;
        // 取平均数和总和
        int c = [array[i] integerValue];
        all += c;
        mid = all/array.count;
        
    }

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