在Javascript中相等运算包括"==","==="，两者不同之处，不必细说。本文主要跟大家探讨如何判断两个对象是否相等。有人可能认为两个对象有相同的属性以及对应的属相有相同的值，那么这两个对象就相等。事实是这样吗？我们验证一下：
var obj0 = {
name: "zhangsan",
age: 18
}
var obj1 = {
name: "zhangsan",
age: 18
}
//Outputs: false
console.log(obj0 == obj1);
//Outputs: false
console.log(obj0 === obj1);
通过例子我们很明显发现，无论是“==”还是“===”都返回false。原因是：基本类型string,number通过值来比较，而对象（Date,Array,Function）及普通对象通过指针指向的内存中的地址来做比较。以上例子我们做个修改就能看出端倪：
var obj0 = {
name: "zhangsan",
age: 18
}
var obj1 = {
name: "zhangsan",
age: 18
}
var obj2 = obj0;
//Outputs: true
console.log(obj0 == obj2);
//Outputs: true
console.log(obj0 === obj2);
//Outputs: false
console.log(obj1 == obj2);
//Outputs: false
console.log(obj1 === obj2);
修改之后返回true。原因是obj0和ob3的指针指向了内存中的同一个地址；这和面向对象的语言（Java/C）中值传递和引用传递的概念相似。如果你想判断两个对象是否相等，首先要明确你是想判断两个对象的属性是否相同，还是属性对应的值是否相同，还是其他。如果你判断两个对象的值是否相等，可以这样：
function isObjectValueEqual(a, b) {
// 获取对象的属性集合（数组）
var aProps = Object.getOwnPropertyNames(a);
var bProps = Object.getOwnPropertyNames(b);
// 属性个数（长度）不同，对象肯定不同
if (aProps.length != bProps.length) {
return false;
}
for (var i = 0; i < aProps.length; i++) {
var propName = aProps[i];
if (a[propName] !== b[propName]) {
return false;
}
}
return true;
}
var obj0 = {
name: "zhangsan",
age: 18
}
var obj1 = {
name: "zhangsan",
age: 18
}
//Outputs: true
console.log(isObjectValueEqual(obj0, obj1));
检查对象的“值相等”我们基本上是要遍历的对象的每个属性，看看它们是否相等。虽然这个简单的实现适用于我们的例子中，但是却不能通用。我们知道JavaScript中的对象不仅仅是例子中的那种简单对象，还有（Array,Date,Function）等等。这样一来我们的方法就会出现判断不出的情况：
1、对象某个属性值为其他对象（Array,Date,String,Function）等
2、对象某个属性值为underfined，另一个对象没有这个属性值
3、对象某个属性值为NaN（未深入研究）
最后经过度娘找到一个检查对象的“值相等”的一个强大的方法，它依靠完善的测试库，涵盖了各种边界情况。Underscore和Lo-Dash有一个名为_.isEqual()方法，用来比较好的处理深度对象的比较。
// Outputs: true
console.log(_.isEqual(obj0, obj1));
// Underscore中isEqual的部分源码
var eq = function(a, b, aStack, bStack) {
// Identical objects are equal. `0 === -0`, but they aren't identical.
// See the [Harmony `egal` proposal](http://wiki.ecmascript.org/doku.php?id=harmony:egal).
if (a === b) return a !== 0 || 1 / a === 1 / b;
// A strict comparison is necessary because `null == undefined`.
if (a == null || b == null) return a === b;
// Unwrap any wrapped objects.
if (a instanceof _) a = a._wrapped;
if (b instanceof _) b = b._wrapped;
// Compare `[[Class]]` names.
var className = toString.call(a);
if (className !== toString.call(b)) return false;
switch (className) {
// Strings, numbers, regular expressions, dates, and booleans are compared by value.
case '[object RegExp]':
// RegExps are coerced to strings for comparison (Note: '' + /a/i === '/a/i')
case '[object String]':
// Primitives and their corresponding object wrappers are equivalent; thus, `"5"` is
// equivalent to `new String("5")`.
return '' + a === '' + b;
case '[object Number]':
// `NaN`s are equivalent, but non-reflexive.
// Object(NaN) is equivalent to NaN
if (+a !== +a) return +b !== +b;
// An `egal` comparison is performed for other numeric values.
return +a === 0 ? 1 / +a === 1 / b : +a === +b;
case '[object Date]':
case '[object Boolean]':
// Coerce dates and booleans to numeric primitive values. Dates are compared by their
// millisecond representations. Note that invalid dates with millisecond representations
// of `NaN` are not equivalent.
return +a === +b;
}
if (typeof a != 'object' || typeof b != 'object') return false;
// Assume equality for cyclic structures. The algorithm for detecting cyclic
// structures is adapted from ES 5.1 section 15.12.3, abstract operation `JO`.
var length = aStack.length;
while (length--) {
// Linear search. Performance is inversely proportional to the number of
// unique nested structures.
if (aStack[length] === a) return bStack[length] === b;
}
// Objects with different constructors are not equivalent, but `Object`s
// from different frames are.
var aCtor = a.constructor, bCtor = b.constructor;
if (
aCtor !== bCtor &&
// Handle Object.create(x) cases
'constructor' in a && 'constructor' in b &&
!(_.isFunction(aCtor) && aCtor instanceof aCtor &&
_.isFunction(bCtor) && bCtor instanceof bCtor)
) {
return false;
}
// Add the first object to the stack of traversed objects.
aStack.push(a);
bStack.push(b);
var size, result;
// Recursively compare objects and arrays.
if (className === '[object Array]') {
// Compare array lengths to determine if a deep comparison is necessary.
size = a.length;
result = size === b.length;
if (result) {
// Deep compare the contents, ignoring non-numeric properties.
while (size--) {
if (!(result = eq(a[size], b[size], aStack, bStack))) break;
}
}
} else {
// Deep compare objects.
var keys = _.keys(a), key;
size = keys.length;
// Ensure that both objects contain the same number of properties before comparing deep equality.
result = _.keys(b).length === size;
if (result) {
while (size--) {
// Deep compare each member
key = keys[size];
if (!(result = _.has(b, key) && eq(a[key], b[key], aStack, bStack))) break;
}
}
}
// Remove the first object from the stack of traversed objects.
aStack.pop();
bStack.pop();
return result;
};
// Perform a deep comparison to check if two objects are equal.
_.isEqual = function(a, b) {
return eq(a, b, [], []);
};
网友评论