Input:2
Output:2
Explanation:
The first beautiful arrangement is [1, 2]:
Number at the 1st position (i=1) is 1, and 1 is divisible by i (i=1).
Number at the 2nd position (i=2) is 2, and 2 is divisible by i (i=2).
The second beautiful arrangement is [2, 1]:
Number at the 1st position (i=1) is 2, and 2 is divisible by i (i=1).
Number at the 2nd position (i=2) is 1, and i (i=2) is divisible by 1.
解法:backtracking
逻辑:
假设我们有个N长的array,我们在array的第一位测试数字1能不能满足条件,如果能满足,我们去到array的下一个位置,测试数字2能不能fit,当1~N全部测试完之后,根据backtraking的特性回弹回:
for i in range(N):
if the i satisfy requirement , put i on current posistion
then we call recusion to the
foo(currentposn+1,arr)
free the arr[i] for the future use
reference:
https://discuss.leetcode.com/topic/79916/java-solution-backtracking/2
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