mysql根据经纬度获取附近的商家

创建测试表

create table geo(
    geo_id INT NOT NULL AUTO_INCREMENT,
    lng float NOT NULL,
    lat float NOT NULL,
    name VARCHAR(100) NULL,
    PRIMARY KEY ( geo_id )
);

插入测试数据

INSERT INTO `geo`(`lng`, `lat`, `name`) VALUES (118.302416,33.958887,"实验小学");
INSERT INTO `geo`(`lng`, `lat`, `name`) VALUES (118.303997,33.95188,"宿迁市人民医院");
INSERT INTO `geo`(`lng`, `lat`, `name`) VALUES (118.302991,33.935828,"宿迁学院");
INSERT INTO `geo`(`lng`, `lat`, `name`) VALUES (118.28215,33.959307,"金陵名府");
INSERT INTO `geo`(`lng`, `lat`, `name`) VALUES (118.290081,33.925404,"润园");
INSERT INTO `geo`(`lng`, `lat`, `name`) VALUES (118.354751,33.959007,"国际馆");

下面是google给的解决方案（基于公里km）。

SELECT  
  geo_id, `name`,(  
    6371 * acos (  
      cos ( radians(33.958887) )  
      * cos( radians( lat ) )  
      * cos( radians( lng ) - radians(118.302416) )  
      + sin ( radians(33.958887) )  
      * sin( radians( lat ) )  
    )  
  ) AS distance  
FROM geo
HAVING distance < 20  
ORDER BY distance 
LIMIT 0 , 20;