Given a binary tree, find the length of the longest path where each node in the path has the same value. This path may or may not pass through the root.
Note: The length of path between two nodes is represented by the number of edges between them.
Example 1:
Input:
5
/ \
4 5
/ \ \
1 1 5
Output:
2
Example 2:
Input:
1
/ \
4 5
/ \ \
4 4 5
Output:
2
Note: The given binary tree has not more than 10000 nodes. The height of the tree is not more than 1000.
package tree;
import com.google.common.collect.Lists;
import java.util.Random;
/**
* Created by cqs on 2018/3/18.
*/
public class LongestUnivaluePath {
private int max = 0;
public static void main(String[] args) {
LongestUnivaluePath lp = new LongestUnivaluePath();
BinaryTree0 bt = new BinaryTree0();
// Integer[] integers = lp.initArray(10);
// Integer[] integers = {5, 4, 5, 1, 1, 5};
Integer[] integers = {26, 26, 26, 26, 26, 24, 26, 25, 25, 25, 27, 23, 25, 25, 27, 24, 26, 24, 26, 24, 24, null, 28, null, null, 26, null, null, 26, 26, 28, 25, null, 25, 27, null, null, null, null, null, 23, null, null, 29, 27, null, null, null, null, 25, null, 27, 27, 24, 26, 24, 26, 26, 26, null, 22, 28, null, 26, 26, null, null, 26, null, 28, 28, 25, null, null, null, 25, 25, 25, 27, 25, 25, 27, 25, null, null, null, null, null, null, null, 27, 27, 27, null, null, 27, 29, 24, 26, 26, 26, null, 26, null, 26, null, null, null, 24, 24, 24, null, 26, 24, 26, null, null, null, 26, null, null, null, 28, null, 30, null, 23, 27, null, null, null, null, null, null, null, null, null, null, null, 23, 25, 25, 25, 27, 25, 23, 25, null, null, null, null, null, null, 29, null, null, null, 26, null, 22, null, null, 26, 24, 26, null, 26, 28, null, null, 26, 22, null, null, null, null, null, null, null, null, null, null, 25, 23, null, null, null, null, 27};
// System.out.println(Lists.newArrayList(integers));
TreeNode root = bt.buildTree(integers);
System.out.println(lp.longestUnivaluePath(root));
}
public int longestUnivaluePath(TreeNode root) {
path(root);
return max;
}
//表示root左边或者右边和node.val相等的路径长度
private int path(TreeNode node) {
if (node == null) return 0;
int left = path(node.left);
int right = path(node.right);
if (node.left == null || node.left.val != node.val) left = 0;
if (node.right == null || node.right.val != node.val) right = 0;
max = Math.max(max, left + right);
return Math.max(left, right) + 1;
}
}
//二叉树
class BinaryTree0 {
private Random random = new Random();
private TreeNode root;
//构建二叉树
TreeNode buildTree(Integer[] arr) {
TreeNode[] nodes = new TreeNode[arr.length];
for (int i = arr.length - 1; i >= 0; --i) {
nodes[i] = arr[i] == null ? null : new TreeNode(arr[i]);
if (nodes[i] == null) continue;
int left = 2 * i + 1;
nodes[i].left = left > (arr.length - 1) ? null : nodes[left];
int right = 2 * (i + 1);
nodes[i].right = right > (arr.length - 1) ? null : nodes[right];
}
return root = nodes[0];
}
//随机生成数组
private Integer[] initArray(int size) {
Integer[] is = new Integer[size];
//
for (int i = 0; i < is.length; i++) {
is[i] = random.nextInt(size * 10);
}
return is;
}
}
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