https://leetcode.com/problems/missing-number/#/description
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n
, find the one that is missing from the array.
For example,Given nums = [0, 1, 3]
return 2
.
Note:Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?
Credits:Special thanks to @jianchao.li.fighter for adding this problem and creating all test cases.
# time O(1)
# space O(1)
# 直接0-n等差求和,减去sum(nums)就是缺失值
class Solution(object):
def missingNumber(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
return sum(range(len(nums) + 1)) - sum(nums)
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