NSMutableArray中removeObjectAtInd

小萌在做开发拖拽单元格移动的时候遇到的坑，这是一个小萌忽略的问题。removeObjectAtIndex和removeObject的两者虽然都是删除，可是却有很大的不同

1、removeObject删除对象

api上是这么解释的。
Removes all occurrences in the array of a given object.
This method uses indexOfObject: to locate matches and then removes them by using removeObjectAtIndex:. Thus, matches are determined on the basis of an object’s response to the isEqual: message. If the array does not contain anObject, the method has no effect (although it does incur the overhead of searching the contents).

删除NSMutableArray中所有isEqual:待删对象的对象

也就是说removeObject:可以删除多个对象（只要符合isEqual:的都删除掉，只要两个对象相等都可以删除掉）。

2、removeObjectAtIndex

api上这样解释的。

Removes the object at index .
To fill the gap, all elements beyond index are moved by subtracting 1 from their index.

Important:Important
Raises an exception NSRangeException if index is beyond the end of the array.

删除指定NSMutableArray中指定index的对象，注意index不能越界，只能删除一个元素。

3、举例说明

tempArray 临时数组
[@"how", @"to", @"remove", @"remove", @"object",@"remove", @"true"]

就拿上面的数组举例吧

（一）removeObject删除

[tempArray removeObject:@"remove"];

输出结果：

//所有@"remove"都被删掉
[@"how", @"to", @"object", @"true"]

（二）removeObjectAtIndex删除

[tempArray removeObjectAtIndex:2];

输出结果：

只删掉一个下标为2的@"remove"元素，其他的都还在
[@"how", @"to", @"remove", @"object",@"remove", @"true"]