Given a list, rotate the list to the right by k places, where k is non-negative.
Example:
Given 1->2->3->4->5->NULL and k = 2,
return 4->5->1->2->3->NULL.
class Solution {
public ListNode rotateRight(ListNode head, int k) {
if(head == null || k == 0){
return head;
}
ListNode p = head;
p = head;
int count = 1;
while(p.next != null){
count++;
p = p.next;
}
p.next = head;
k = k % count;
for(int i = 0; i < count - k; i++){
p = p.next;
}
head = p.next;
p.next = null;
return head;
}
}
网友评论