题目
Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array.
答案
class Solution {
public int[] countBits(int num) {
int[] f = new int[num + 1];
f[0] = 0;
for(int i = 1; i <= num; i++) {
int shift2 = i >> 1;
f[i] = f[shift2] + (i % 2);
}
return f;
}
}
题目Given a non negative integer number num. For every numb...
Counting Bits 典型的动态规划
https://leetcode.com/problems/counting-bits/ Given a non ...
LeetCode 338. Counting Bits Description Given a non negat...
倒过来想，一个数 * 2 就是把它的二进制全部左移一位，也就是说 1的个数是相等的。 那么我们可以利用这个结论来做...
Given a non negative integer number num. For every number...
Given a non negative integer number num. For every number...
338. Counting Bits Given a non negative integer number nu...
题目描述 338. Counting Bits Given a non negative integer numb...
Counting Bits [method1] naive O(n*sizeof(int)) side note ...
本文标题：Counting Bits
本文链接：https://www.haomeiwen.com/subject/teqknftx.html
网友评论