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坐标 多种数据库计算GPS经纬度坐标距离

坐标 多种数据库计算GPS经纬度坐标距离

作者: 不玩了啊 | 来源:发表于2019-12-03 14:30 被阅读0次

mysql计算GPS经纬度距离

DELIMITER $$

CREATEDEFINER=`root`@`localhost` FUNCTION`getDistance`(

lon1 float(10,7)

,lat1 float(10,7)

,lon2 float(10,7)

,lat2 float(10,7)

) RETURNSdouble

begin

declared double;

declareradius int;

setradius = 6378140; #假设地球为正球形,直径为6378140米

setd = (2*ATAN2(SQRT(SIN((lat1-lat2)*PI()/180/2)

*SIN((lat1-lat2)*PI()/180/2)+

COS(lat2*PI()/180)*COS(lat1*PI()/180)

*SIN((lon1-lon2)*PI()/180/2)

*SIN((lon1-lon2)*PI()/180/2)),

SQRT(1-SIN((lat1-lat2)*PI()/180/2)

*SIN((lat1-lat2)*PI()/180/2)

+COS(lat2*PI()/180)*COS(lat1*PI()/180)

*SIN((lon1-lon2)*PI()/180/2)

*SIN((lon1-lon2)*PI()/180/2))))*radius;

returnd;

end

sqlServer计算GPS经纬度距离

SET ANSI_NULLS ON

GO

SET QUOTED_IDENTIFIER ON

GO

CREATE FUNCTION [dbo].[getDistance](@lng1 FLOAT,@lat1 FLOAT,@lng2 FLOAT,@lat2 FLOAT)

RETURNS FLOAT

AS

BEGIN

        DECLARE @Distance      FLOAT

        DECLARE @EARTH_RADIUS  FLOAT

        SET @EARTH_RADIUS = 6378140

        DECLARE @RadLatBegin  FLOAT,

                @RadLatEnd    FLOAT,

                @RadLatDiff  FLOAT,

                @RadLngDiff  FLOAT

        SET @RadLatBegin = @lat1 *PI()/ 180.0

        SET @RadLatEnd = @lat2 *PI()/ 180.0

        SET @RadLatDiff = @RadLatBegin - @RadLatEnd

        SET @RadLngDiff = @lng1 *PI()/ 180.0 - @lng2 *PI()/ 180.0

        SET @Distance = 2 *ASIN(

                SQRT(

                    POWER(SIN(@RadLatDiff / 2), 2)+COS(@RadLatBegin)*COS(@RadLatEnd)

                    *POWER(SIN(@RadLngDiff / 2), 2)

                )

            )

        SET @Distance =ROUND(@Distance * @EARTH_RADIUS,1)

        --SET @Distance = Round(@Distance * 10000) / 10000

        RETURN @Distance

END

Oracle计算GPS经纬度距离

create or replace FUNCTION GET_DISTANCE

(

  LNG1 IN NUMBER,

  LAT1 IN NUMBER,

  LNG2 IN NUMBER,

  LAT2 IN NUMBER

) RETURN NUMBER IS

  DISTANCE NUMBER:=0;

  PI NUMBER:=3.141592625;

  EARTH_RADIUS NUMBER :=6378140;

  RADLATBEGIN NUMBER :=LAT1*PI/180.0;

  RADLATEND NUMBER :=LAT2*PI/180.0;

  RADLATDIFF NUMBER :=RADLATBEGIN-RADLATEND;

  RADLNGDIFF NUMBER :=LNG1*PI/180.0-LNG2*PI/180.0;

BEGIN

  DISTANCE:=2*ASIN(SQRT(POWER(SIN(RADLATDIFF/2),2)+COS(RADLATBEGIN)*COS(RADLATEND)*POWER(SIN(RADLNGDIFF/2),2)));

  DISTANCE:=ROUND(DISTANCE*EARTH_RADIUS,1);

  RETURN DISTANCE;

END GET_DISTANCE;

PHP计算GPS经纬度坐标

<?php

functionrad($d){

return$d* 3.1415926535898 / 180.0;

}

functionGetDistance($lat1, $lng1, $lat2, $lng2){

$EARTH_RADIUS= 6378.137;

$radLat1= rad($lat1);

$radLat2= rad($lat2);

$a= $radLat1- $radLat2;

$b= rad($lng1) - rad($lng2);

$s= 2 * asin(sqrt(pow(sin($a/2),2) + cos($radLat1)*cos($radLat2)*pow(sin($b/2),2)));

$s= $s*$EARTH_RADIUS;

$s= round($s* 10000) / 10000;

return$s;

}

echoGetDistance(116.480733,39.98684,117.480733,39.98684);

?>

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版权声明:本文为CSDN博主「_yuki_」的原创文章,遵循 CC 4.0 BY-SA 版权协议,转载请附上原文出处链接及本声明。

原文链接:https://blog.csdn.net/qq_19707521/article/details/70800933

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