2018-12-26 输出不能被7整除的数和总和（每行四个）

 Console.WriteLine("1-100以内所有不能被7整除的数");
            int Count = 0;
             int Sum = 0;
             for (int i = 1; i <= 100; i++)
             {
                 if (!(i % 7 == 0))
                 {
                     Count++;
                     Sum += i;
                     Console.Write("{0} ", i);
                     if (Count % 4 == 0)
                     {
                         Console.WriteLine("");
                     }
                 }
             }
             Console.WriteLine("和为：{0}", Sum);
             Console.ReadKey();