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(LeetCode 561-Easy)Array Partiti

(LeetCode 561-Easy)Array Partiti

作者: Demi_yu | 来源:发表于2017-06-23 10:02 被阅读0次

https://leetcode.com/problems/array-partition-i

Description

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.

Example 1:

Input: [1,4,3,2]

Output: 4
Explanation: n is 2, and the maximum sum of pairs is 4 = min(1, 2) + min(3, 4).

Note:

  1. n is a positive integer, which is in the range of [1, 10000].
  2. All the integers in the array will be in the range of [-10000, 10000].

问题分析:

由题意可知,我们可以将整个数组升序排序,每两个数为一组,取其最小的那个值相加,最终得到答案。

过程详见代码:

python

class Solution(object):

    def arrayPairSum(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        return sum(sorted(nums)[::2])

class Solution(object):
    def arrayPairSum(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        
        nums.sort()
        return sum(nums[::2])

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