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数据库基础

数据库基础

作者: 1baibai | 来源:发表于2021-11-09 17:28 被阅读0次
1. 数据库(DDL)

  • 数据库创建
create database if not exists 1baibai charset utf8;
  • 删除数据库
drop database if exists 1baibai;
  • 修改数据库
alter database 1baibai character set utf8;
2. 表(DDL)

  • 表创建
CREATE TABLE `job` (
  `id` int unsigned NOT NULL AUTO_INCREMENT,
  `job_name` varchar(255) DEFAULT NULL,
  `create_time` datetime DEFAULT NULL,
  `create_people` varchar(255) DEFAULT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
  • 查看所有表
show tables;
  • 查看表结构
 desc job;
  • 查看建表语句
show create table job;
  • 修改表
    1. 添加字段
    ALTER TABLE job ADD (`des` varchar(255), `job_people` varchar(255));
    
    1. 修改字段类型
    ALTER TABLE job MODIFY des int;
    
    1. 修改字段名
    ALTER table job CHANGE des description VARCHAR(255);
    
    1. 删除字段
    ALTER TABLE job DROP create_time;
    
    1. 修改表名称
    ALTER TABLE job RENAME TO jobs;
    
    1. 删除主键
    ALTER TABLE jobs DROP PRIMARY KEY;
    
    7.修改表时添加主键
    ALTER TABLE jobs ADD PRIMARY KEY(des);
    
    8.设置主键自增长和非空约束
    ALTER TABLE place ADD PRIMARY KEY(id);
    ALTER TABLE place CHANGE id id INT NOT NULL auto_increment;
    
    9.设置字段唯一约束
    ALTER TABLE place CHANGE id id INT NOT NULL UNIQUE;
    
3. 数据操作(DML)
  • 插入数据
INSERT INTO jobs (job_name, create_people, description) VALUES ('iOS', 'Bill', 'iOS开发招聘');

INSERT INTO jobs VALUES (2, 'Java', 'linda', 'Java开发招聘');
  • 修改数据
UPDATE jobs SET job_name = 'android' WHERE id = 2;
  • 删除数据
DELETE FROM jobs WHERE id = 3;
4. 查询
  • 基本查询
SELECT * FROM jobs;
  • 查询指定列
SELECT job_name, create_people FROM jobs;
  • 去重
SELECT DISTINCT job_name, create_people FROM jobs;
  • 列运算
    1. 数量类型:+、-、、/
    SELECT age * 5 FROM jobs;
    
    1. 字符串克拼接
    SELECT CONCAT('&&&',create_people) FROM jobs;
    
    1. NULL值转换
    SELECT job_name, IFNULL('空',des) FROM jobs;
    
    4.给列起别名
    SELECT job_name AS '职位', create_people AS '创建人', description AS '描述', IFNULL(des,0) AS '备注' FROM jobs;
    
  • 条件控制
    1.条件查询
    SELECT * FROM jobs WHERE id BETWEEN 13 AND 16 AND des IS NOT  NULL;
    
    1. 模糊查询
    SELECT * FROM jobs WHERE create_people LIKE '%B%';
    SELECT * FROM jobs WHERE create_people LIKE 'B___';
    
    1. 排序
    SELECT * FROM jobs ORDER BY id ASC;
    SELECT * FROM jobs ORDER BY id DESC;
    SELECT * FROM jobs ORDER BY age ASC, id DESC;
    
5. 聚合函数
  1. 列函数统计(不为NULL)
SELECT COUNT(des) FROM jobs;

2.最大值查询

SELECT MAX(age) FROM jobs;

3.最小值查询

SELECT MIN(age) FROM jobs;

4.和查询

SELECT SUM(age) FROM jobs;
  1. 平均值查询
SELECT AVG(age) FROM jobs;
6.分组查询
SELECT job_name, COUNT(*) FROM jobs GROUP BY id;
7.限定查询
SELECT * from jobs LIMIT 1,5;

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