身份证校验

我们知道涉及到借贷、信用卡申请类似的项目都用户的身份信息都是比较敏感的，所以经常要去验证用户的身份信息，其中身份证的信息验证是比较麻烦的，所以自己也整理了一份相关的校验方式供大家参考。

一、省份

每个省都有对应的编号：

const city = {
    11: "北京",
    12: "天津",
    13: "河北",
    14: "山西",
    15: "内蒙古",
    21: "辽宁",
    22: "吉林",
    23: "黑龙江 ",
    31: "上海",
    32: "江苏",
    33: "浙江",
    34: "安徽",
    35: "福建",
    36: "江西",
    37: "山东",
    41: "河南",
    42: "湖北 ",
    43: "湖南",
    44: "广东",
    45: "广西",
    46: "海南",
    50: "重庆",
    51: "四川",
    52: "贵州",
    53: "云南",
    54: "西藏 ",
    61: "陕西",
    62: "甘肃",
    63: "青海",
    64: "宁夏",
    65: "新疆",
    71: "台湾",
    81: "香港",
    82: "澳门",
    91: "国外 "
};

二、生日

这里只考虑18位的身份证，15位一代身份证暂不列入考虑范围：

const validBirthday = idcard => {
    //身份证18位时，次序为省（3位）市（3位）年（4位）月（2位）日（2位）校验位（4位），校验位末尾可能为X
    let re_eighteen = /^(\d{6})(\d{4})(\d{2})(\d{2})(\d{3})([0-9]|X|x|\*)$/i;
    let arr_data = idcard.match(re_eighteen);
    let year = arr_data[2];
    let month = arr_data[3];
    let day = arr_data[4];
    let birthday = new Date(year + '/' + month + '/' + day);
    return validDate(year, month, day, birthday);
    return false;
}

三、日期

日期的合法性是通过生日来推算：

const validDate = (year, month, day, birthday) => {
    let now = new Date();
    let now_year = now.getFullYear();
    //年月日是否合理
    if (birthday.getFullYear() == year && (birthday.getMonth() + 1) == month && birthday.getDate() == day) {
        //判断年份的范围（0岁到100岁之间)
        let time = now_year - year;
        if (time >= 0 && time <= 100) {
            return true;
        }
        return false;
    }
    return false;
}

最后整合成完整的身份证校验：

const validIDcard = idcard => {
    idcard = idcard.replace(/\*/g, 'X');
    idcard = idcard.replace(/x/g, 'X');
    let pass = true;
    let checkReg = null;
    let carid_check = /(^\d{18}$)|(^\d{17}(\d|X|x|\*)$)/i;
    if (!idcard || !carid_check.test(idcard)) { //基本长度，格式校验
        pass = false;
    } else if (!city[idcard.substr(0, 2)]) { //省份校验
        pass = false;
    } else if (!validBirthday(idcard)) {
        pass = false;
    } else {
        if (parseInt(idcard.substr(6, 4) % 4 == 0 || (parseInt(idcard.substr(6, 4)) % 100 == 0 && parseInt(idcard.substr(6, 4)) % 4 == 0))) {
            checkReg = /^[1-9][0-9]{5}19[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}[0-9Xx*]$/i; //闰年出生日期的合法性正则表达式
        } else {
            checkReg = /^[1-9][0-9]{5}19[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}[0-9Xx*]$/i; //平年出生日期的合法性正则表达式
        }
        //18位身份证需要验证最后一位校验位
        if (checkReg.test(idcard)) {
            idcard = idcard.split('');
            //∑(ai×Wi)(mod 11)
            //加权因子
            let factor = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2];
            //校验位
            let parity = [1, 0, 'X', 9, 8, 7, 6, 5, 4, 3, 2];
            let sum = 0;
            let ai = 0;
            let wi = 0;
            for (let i = 0; i < 17; i++) {
                ai = idcard[i];
                wi = factor[i];
                sum += ai * wi;
            }
            let last = parity[sum % 11];
            if (parity[sum % 11] != idcard[17]) {
                pass = false;
            }
        }
    }
    return pass;
}

现在直接调用validIDcard传入你的身份证试试吧。