ssm项目中request获取请求json格式的数据

request.getParameter只能请求一些key value的数据，如果前端请求了如下截图中的post数据json格式,该如何接收呢？

通常情况下request传输这种json数据是通过InputStream流的方式，所以可以通过request.getInputStream() 获取流再转成String 字符串再转成com.alibaba.fastjson.JSONObject; 就可以拿到参数了
实例如下 controller 方法：

 /**
     * 获取库存数据
     */
    public void getStockInfoData() {
        HttpServletRequest request = getRequest();
        //request.getParameter(name)
        HttpServletResponse response = getResponse();
        JSONObject paramsObj = AppFrameworkUtil.getRequestParamsObj(request);
        Map<String, Object> paramsMap = new HashMap<String, Object>();
        paramsMap.put("userId", "44A50");
        paramsMap.put("ym", paramsObj.getString("ym"));//"201906"
        paramsMap.put("dealerId", paramsObj.getString("dealerId"));//"44A50"
        paramsMap.put("modelId", "-1");
        
        String json = dlrHomePageService.getStockInfoData(request, paramsMap);
        AppFrameworkUtil.renderJSON(response, json);
    }

AppFrameworkUtil.getRequestParamsObj方法实现

/**
     * 返回jsonObj参数
     * @param request
     * @return
     */
    public static JSONObject getRequestParamsObj(HttpServletRequest request) {
        JSONObject paramsObj = new JSONObject();
        try {
            BufferedReader streamReader = new BufferedReader( new InputStreamReader(request.getInputStream(), "UTF-8"));
            StringBuilder responseStrBuilder = new StringBuilder();
            String inputStr;
            while ((inputStr = streamReader.readLine()) != null)
                responseStrBuilder.append(inputStr);
            
            paramsObj = JSONObject.parseObject(responseStrBuilder.toString());
            
        } catch (Exception e) {
            e.printStackTrace();
        }
        return paramsObj;
    }

如此 通过paramsObj.getString(key)的方式就能拿到参数。