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2018小米软开笔试第一题

2018小米软开笔试第一题

作者: Yuu_CX | 来源:发表于2017-09-18 21:06 被阅读0次
    image.png
    image.png
    package leetcode;
    
    /**
     * @author Yu
     * @date 2017年9月18日
     * 
     * 2018小米软开笔试第一题
     */
    
    import java.util.Scanner;
    
    public class Xiaomi_Main {
    
        private static String res = null;
    
        public static void main(String[] args) {
            Scanner sc = new Scanner(System.in);
            while (sc.hasNext()) {
                String str = sc.next();
                str = Exg(str);
                res = str.toUpperCase();
                System.out.println(res);
            }
            sc.close();
    //      System.out.println(Exg("MY.ASTParser12").toUpperCase());
        }
    
        public static String Exg(String str) {
            if (str == null)
                return null;
            str = "_" + str + "_";
            str = str.replace('.', '_');
            char[] c = new char[str.length()+1000];
            int j = 0;
            for (int i = 0; i < str.length(); i++) {
                if ((('a' <= str.charAt(i) && str.charAt(i) <= 'z')
                        && ('A' <= str.charAt(i + 1) && str.charAt(i + 1) <= 'Z'))) {
                    c[j++] = str.charAt(i);
                    c[j++] = '_';
                } else if ((('A' <= str.charAt(i) && str.charAt(i) <= 'Z')
                        && ('A' <= str.charAt(i + 1) && str.charAt(i + 1) <= 'Z')
                        && ('a' <= str.charAt(i + 2) && str.charAt(i + 2) <= 'z'))) {
                    c[j++] = str.charAt(i);
                    c[j++] = '_';
                } else if ((('A' <= str.charAt(i) && str.charAt(i) <= 'Z')
                        || ('a' <= str.charAt(i) && str.charAt(i) <= 'z'))
                        && ('0' <= str.charAt(i + 1) && str.charAt(i + 1) <= '9')) {
                    c[j++] = str.charAt(i);
                    c[j++] = '_';
                } else if (('0' <= str.charAt(i) && str.charAt(i) <= '9')
                        && (('A' <= str.charAt(i + 1) && str.charAt(i + 1) <= 'Z')
                                || ('a' <= str.charAt(i + 1) && str.charAt(i + 1) <= 'z'))) {
                    c[j++] = str.charAt(i);
                    c[j++] = '_';
                } else {
                    c[j++] = str.charAt(i);
                }
                
            }
            
            String ss = String.valueOf(c);
            ss = ss.trim();//用trim()函数去除字符串首尾的空格
            return ss;
        }
    }
    

    大佬用C++ KMP写的,膜拜下

    #include <cstdio>
    #include <cstring>
    #include <iostream>
    #include <string>
    #include <algorithm>
    #include <cstdlib>
    #include <vector>
    #include <map>
    
    using namespace std;
    
    const int maxn = 10007;
    
    char s1[maxn], s2[maxn], s3[maxn];
    int ne[maxn], loc[maxn];
    int vis[30];
    int n, l1, l2;
    int ans, s, e;
    void getNext() {
        int k = -1;
        ne[0] = -1;
        for (int i = 1; i < l2; i++) {
            while (k != -1 && s2[i] != s2[k + 1]) {
                k = ne[k];
            }
            if (s2[i] == s2[k + 1]) {
                k++;
            }
            ne[i] = k;
        }
    }
    
    void getAns() {
        int k = -1;
        for (int i = 0; i < n; i++) {
            while (k != -1 && s3[i] != s2[k + 1]) {
                k = ne[k];
            }
            if (s3[i] == s2[k + 1]) {
                k++;
            }
            if (k == l2 - 1) {
                int temp = loc[i] - loc[i + 1 - l2];
                if (temp < ans) {
                    ans = temp;
                    s = loc[i + 1 - l2];
                    e = loc[i];
                }
                k = ne[k];
            }
        }
    }
    
    int main() {
    //    freopen("in.txt", "r", stdin);
        while (scanf("%s%s", &s1, s2) != EOF) {
            memset(vis, 0, sizeof(vis));
            l2 = strlen(s2);
            l1 = strlen(s1);
            ans = l1 + 1;
            s = -1;
            e = -1;
            for (int i = 0; i < l2; i++) {
                vis[s2[i] - 'a'] = 1;
            }
            n = 0;
            for (int i = 0; i < l1; i++) {
                if (vis[s1[i] - 'a']) {
                    s3[n] = s1[i];
                    loc[n] = i;
                    n++;
                }
            }
            s3[n] = '\0';
    //        printf("%s\n", s3);
            getNext();
            getAns();
            printf("%d %d\n", s, e);
        }
        return 0;
    }
    

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