36. 有效的数独

作者: 花果山松鼠 | 来源:发表于2018-09-21 11:15 被阅读0次

    一、题目原型:

    判断一个 9x9 的数独是否有效。只需要根据以下规则,验证已经填入的数字是否有效即可。

    数字 1-9 在每一行只能出现一次。
    数字 1-9 在每一列只能出现一次。
    数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。

    二、题目意思剖析:

    输入:
    [
    ["5","3",".",".","7",".",".",".","."],
    ["6",".",".","1","9","5",".",".","."],
    [".","9","8",".",".",".",".","6","."],
    ["8",".",".",".","6",".",".",".","3"],
    ["4",".",".","8",".","3",".",".","1"],
    ["7",".",".",".","2",".",".",".","6"],
    [".","6",".",".",".",".","2","8","."],
    [".",".",".","4","1","9",".",".","5"],
    [".",".",".",".","8",".",".","7","9"]
    ]
    输出: true
    

    三、解题思路:

    数独,应该大家都玩过,其实就只是判断三个点,横、竖、3*3的方格。

    func isValidSudoku(_ board: [[Character]]) -> Bool {
    
        var bool: Bool = true
        
        for i in 0..<board.count {
            
            let characters = board[i]
            var mutCharacters1: [Character] = []
            var mutCharacters2: [Character] = []
            for j in 0..<characters.count {
                
                // 1.每行比较
                let character1 = board[i][j]
                if character1 != "." {
                    mutCharacters1.append(character1)
                }
                
                // 2.每列比较
                let character2 = board[j][i]
                if character2 != "." {
                    mutCharacters2.append(character2)
                }
                
                if j == characters.count - 1 {
                    
                    let set1: Set = Set(mutCharacters1)
                    if set1.count == mutCharacters1.count {
                        bool = true
                    }else {
                        bool = false
                        return bool
                    }
                    
                    let set2: Set = Set(mutCharacters2)
                    if set2.count == mutCharacters2.count {
                        bool = true
                    }else {
                        bool = false
                        return bool
                    }
                }
            }
        }
        
        var index_i = 0
        var index_j = 0
        while index_i<board.count {
            
            // 3.每方格
            while index_j<board[0].count {
                
                var square: [Character] = []
                if board[index_i][index_j] != "." {
                    square.append(board[index_i][index_j])
                }
                if board[index_i+1][index_j] != "." {
                    square.append(board[index_i+1][index_j])
                }
                if board[index_i+2][index_j] != "." {
                    square.append(board[index_i+2][index_j])
                }
                if board[index_i][index_j+1] != "." {
                    square.append(board[index_i][index_j+1])
                }
                if board[index_i+1][index_j+1] != "." {
                    square.append(board[index_i+1][index_j+1])
                }
                if board[index_i+2][index_j+1] != "." {
                    square.append(board[index_i+2][index_j+1])
                }
                if board[index_i][index_j+2] != "." {
                    square.append(board[index_i][index_j+2])
                }
                if board[index_i+1][index_j+2] != "." {
                    square.append(board[index_i+1][index_j+2])
                }
                if board[index_i+2][index_j+2] != "." {
                    square.append(board[index_i+2][index_j+2])
                }
                
                if index_j % 3 == 0 {
                    let set: Set = Set(square)
                    if set.count == square.count {
                        bool = true
                    }else {
                        bool = false
                        return bool
                    }
                }
                // 因为是3*3的小方格,所以需要+3,而不是再+1了
                index_j = index_j + 3
            }
            index_i = index_i + 3
            // 因为index_j循环后变成了9,需要设置为0
            index_j = 0
        }
        return bool
    }
    

    四、小结

    耗时72毫秒,超过73.77%的提交记录,总提交数504

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