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iOS开发中,常用判断的方法,希望大家可以记一下,肯定有用!
//获取字符串(或汉字)首字母
+ (NSString *)firstCharacterWithString:(NSString *)string{
NSMutableString *str = [NSMutableString stringWithString:string];
CFStringTransform((CFMutableStringRef)str,NULL, kCFStringTransformMandarinLatin,NO);
CFStringTransform((CFMutableStringRef)str,NULL, kCFStringTransformStripDiacritics,NO);
NSString *pingyin = [str capitalizedString];
return [pingyin substringToIndex:1];
}
//判断手机号码格式是否正确
+ (BOOL)valiMobile:(NSString *)mobile{
mobile = [mobile stringByReplacingOccurrencesOfString:@" "withString:@""];
if(mobile.length !=11)
{
returnNO;
}else{
/**
*移动号段正则表达式
*/
NSString *CM_NUM =@"^((13[4-9])|(147)|(15[0-2,7-9])|(178)|(18[2-4,7-8]))\\d{8}|(1705)\\d{7}$";
/**
*联通号段正则表达式
*/
NSString *CU_NUM =@"^((13[0-2])|(145)|(15[5-6])|(176)|(18[5,6]))\\d{8}|(1709)\\d{7}$";
/**
*电信号段正则表达式
*/
NSString *CT_NUM =@"^((133)|(153)|(177)|(18[0,1,9]))\\d{8}$";
NSPredicate *pred1 = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", CM_NUM];
BOOL isMatch1 = [pred1 evaluateWithObject:mobile];
NSPredicate *pred2 = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", CU_NUM];
BOOL isMatch2 = [pred2 evaluateWithObject:mobile];
NSPredicate *pred3 = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", CT_NUM];
BOOL isMatch3 = [pred3 evaluateWithObject:mobile];
if(isMatch1 || isMatch2 || isMatch3) {
return YES;
}else{
return NO;
}
}
}
//判断注册邮箱是否正确
+ (BOOL)isAvailableEmail:(NSString *)email {
NSString *emailRegex =@"[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}";
NSPredicate *emailTest = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", emailRegex];
return [emailTest evaluateWithObject:email];
}
//判断字符串中是否含有空格
+ (BOOL)isHaveSpaceInString:(NSString *)string{
NSRange _range = [string rangeOfString:@" "];
if(_range.location != NSNotFound) {
return YES;
}else{
return NO;
}
}
//判断字符串中是否含有某个字符串
+ (BOOL)isHaveString:(NSString *)string1 InString:(NSString *)string2{
NSRange _range = [string2 rangeOfString:string1];
if(_range.location != NSNotFound) {
return YES;
}else{
return NO;
}
}
//判断字符串中是否含有中文
+ (BOOL)isHaveChineseInString:(NSString *)string{
for(NSInteger i =0; i < [string length]; i++){
inta = [string characterAtIndex:i];
if(a >0x4e00&& a <0x9fff) {
return YES;
}
}
return NO;
}
//判断字符串是否全部为数字
+ (BOOL)isAllNum:(NSString *)string{
unichar c;
for(int i=0; i<string.length;i++){
c=[string characterAtIndex:i];
if(!isdigit(c)) {
return NO;
}
}
return YES;
}
//校验身份证号码(老的15位,新的18位)
- (BOOL)isAllIDcard:(NSString *)card{
//15位
NSString* number1=@"^[1-9]\\d{7}((0\\d)|(1[0-2]))(([0|1|2]\\d)|3[0-1])\\d{3}$";
NSPredicate * numberPre1 = [NSPredicate predicateWithFormat:@"SELF MATCHES %@",number1];
BOOL isOK1 = [numberPre1 evaluateWithObject:card];
//18位
NSString* number2=@"^[1-9]\\d{5}[1-9]\\d{3}((0\\d)|(1[0-2]))(([0|1|2]\\d)|3[0-1])\\d{3}([0-9]|X)$";
NSPredicate * numberPre2 = [NSPredicate predicateWithFormat:@"SELF MATCHES %@",number2];
BOOL isOK2 = [numberPre2 evaluateWithObject:card];
if(isOK1 || isOK2) {
return YES;
}
return NO;
}
//检查数组,字典,字符串是否为空.
+(BOOL)isNilOfSender:(NSObject *)sender{
if(!sender) {
returnYES;
}
if([sender isKindOfClass:[NSArray class]]) {
NSArray *array = (NSArray *)sender;
if(array.count) {
return NO;
}else{
return YES;
}
}
if([sender isKindOfClass:[NSDictionary class]]) {
NSDictionary *dic = (NSDictionary *)sender;
if([dic allKeys].count) {
return NO;
}else{
return YES;
}
}
if([sender isKindOfClass:[NSString class]]) {
NSString *str = (NSString *)sender;
if(str !=NULL&& [str stringByReplacingOccurrencesOfString:@" "withString:@""].length >0) {
return NO;
}
else{
return YES;
}
}
return YES;
}
时间: 2016.12.5 11:31 am
声明
- 所有文章出自 Kenny Hito 的博客 !
- 未经本人允许不得转载, 转载请标明来源与作者, 谢谢合作!
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