844. 比较含退格的字符串
作者:
上杉丶零 | 来源:发表于
2019-02-18 21:47 被阅读0次class Solution {
public boolean backspaceCompare(String S, String T) {
Stack<Character> cStack1 = new Stack<Character>();
Stack<Character> cStack2 = new Stack<Character>();
for (char c : S.toCharArray()) {
if (c != '#') {
cStack1.push(c);
} else if (!cStack1.isEmpty()) {
cStack1.pop();
}
}
for (char c : T.toCharArray()) {
if (c != '#') {
cStack2.push(c);
} else if (!cStack2.isEmpty()) {
cStack2.pop();
}
}
return cStack1.equals(cStack2);
}
}

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本文标题:844. 比较含退格的字符串
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