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16. 3Sum Closest

16. 3Sum Closest

作者: liuhaohaohao | 来源:发表于2018-06-26 20:13 被阅读0次

    Given an array nums of n integers and an integer target, find three integers in nums such that the sum is closest to target. Return the sum of the three integers. You may assume that each input would have exactly one solution.

    Example:

    Given array nums = [-1, 2, 1, -4], and target = 1.
    
    The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
    

    Solution

    class Solution {
        public int threeSumClosest(int[] nums, int target) {
            Arrays.sort(nums);
            int result = nums[0] + nums[1] + nums[2];       //临时值
    
            for (int i = 0; i < nums.length - 2; i++){          
                int j = i + 1;
                int k = nums.length - 1;
                
                while (j < k){
                    int sum = nums[j] + nums[k] + nums[i];
                    if (sum == target){
                        return target;
                    }else if (sum > target){
                        k--;
                    }else if (sum < target){
                        j++;
                    }
                    if (Math.abs(sum - target) < Math.abs(result - target)){
                        result = sum;                       //找最接近的加和
                    }        
                }
            }
            return result;
        }
    }
    

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