/*
Time:2019.12.5
Author: Goven
type:水题
ref:
*/
#include<iostream>
#include<string>
using namespace std;
int main()
{
string a, b;
int la, lb, sum = 0;
cin >> a >> b;
la = a.length();
lb = b.length();
for (int i = 0; i < la; i++) {
for (int j = 0; j < lb; j++) {
sum += (a[i] - '0') * (b[j] - '0');
}
}
cout << sum << endl;
return 0;
}
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