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16. 3Sum Closest

16. 3Sum Closest

作者: Nancyberry | 来源:发表于2018-05-24 03:42 被阅读0次

    Description

    Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.

    For example, given array S = {-1 2 1 -4}, and target = 1.

    The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).

    Solution

    Three-pointers, O(n^2) time

    class Solution {
        public int threeSumClosest(int[] nums, int target) {
            int res = nums[0] + nums[1] + nums[2];  // important, don't set to MAX_VALUE
            Arrays.sort(nums);
            int i = 0;
            int n = nums.length;
            
            while (i < n) {
                int j = i + 1;
                int k = n - 1;
                while (j < k) {
                    int sum = nums[i] + nums[j] + nums[k];
                    
                    if (sum < target) {
                        ++j;
                    } else if (sum > target) {
                        --k;
                    } else {
                        return sum;
                    }
                    
                    if (Math.abs(sum - target) < Math.abs(res - target)) {
                        res = sum;
                    }
                }
                ++i;
            }
            
            return res;
        }
    }
    

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