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算法题--将矩阵中0所在的行和列置0

算法题--将矩阵中0所在的行和列置0

作者: 岁月如歌2020 | 来源:发表于2020-04-19 22:31 被阅读0次
    image.png

    0. 链接

    题目链接

    1. 题目

    Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in-place.

    Example 1:

    Input: 
    [
      [1,1,1],
      [1,0,1],
      [1,1,1]
    ]
    Output: 
    [
      [1,0,1],
      [0,0,0],
      [1,0,1]
    ]
    

    Example 2:

    Input: 
    [
      [0,1,2,0],
      [3,4,5,2],
      [1,3,1,5]
    ]
    Output: 
    [
      [0,0,0,0],
      [0,4,5,0],
      [0,3,1,0]
    ]
    

    Follow up:

    A straight forward solution using O(mn) space is probably a bad idea.
    A simple improvement uses O(m + n) space, but still not the best solution.
    Could you devise a constant space solution?

    2. 思路1:两次遍历+第0行/列单独处理

    1. 标志位分配
    • 用first_col_zero(True/False)来记录第0列是否需要全部置0
    • 用matrix[i][0]记录第i行是否需要全部置为0, 其中0 <= i <= m - 1
    • 用matrix[0][j]记录第j列是否需要全部置为0, 其中1 <= j <= n - 1
    1. 算法过程: 2次遍历
    • 第1次通过遍历 0 <= i <= m - 1 和 1 <= j <= n - 1来设置标志位
    • 第2次遍历先试图对行(1-m)且列(1-n)的格子置0,再对第0行/列则单独尝试置0

    3. 代码

    class Solution:
        def setZeroes(self, matrix: List[List[int]]) -> None:
            first_col_zero = False
            m = len(matrix)
            n = len(matrix[0])
    
            for i in range(m):
                if matrix[i][0] == 0:
                    first_col_zero = True
                for j in range(1, n):
                    if matrix[i][j] == 0:
                        matrix[0][j] = 0
                        matrix[i][0] = 0
    
            for i in range(1, m):
                for j in range(1, n):
                    if matrix[i][0] == 0 or matrix[0][j] == 0:
                        matrix[i][j] = 0
    
            if matrix[0][0] == 0:
                for j in range(1, n):
                    matrix[0][j] = 0
    
            if first_col_zero:
                for i in range(1, m):
                    matrix[i][0] = 0
    
    
    def print_matrix(matrix):
        for each in matrix:
            print(each)
        print('=' * 50)
    
    
    def my_test(solution, matrix):
        print('input:')
        print_matrix(matrix)
        solution.setZeroes(matrix)
        print('output:')
        print_matrix(matrix)
    
    
    solution = Solution()
    my_test(solution, [
        [1, 1, 1],
        [1, 0, 1],
        [1, 1, 1]
    ])
    my_test(solution, [
        [0, 1, 2, 0],
        [3, 4, 5, 2],
        [1, 3, 1, 5]
    ])
    
    

    输出结果

    input:
    [1, 1, 1]
    [1, 0, 1]
    [1, 1, 1]
    ==================================================
    output:
    [1, 0, 1]
    [0, 0, 0]
    [1, 0, 1]
    ==================================================
    input:
    [0, 1, 2, 0]
    [3, 4, 5, 2]
    [1, 3, 1, 5]
    ==================================================
    output:
    [0, 0, 0, 0]
    [0, 4, 5, 0]
    [0, 3, 1, 0]
    ==================================================
    

    4. 结果

    image.png

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