美文网首页
LeetCode每日一题:length of last word

LeetCode每日一题:length of last word

作者: yoshino | 来源:发表于2017-06-07 16:31 被阅读6次

问题描述

Given a string s consists of upper/lower-case alphabets and empty space characters' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s ="Hello World",
return5.

问题分析

很容易的一道题,看代码就行了。

代码实现

    public int lengthOfLastWord(String s) {
        String[] str = s.split(" ");
        if (str.length == 0) return 0;
        return str[str.length - 1].length();
    }

相关文章

网友评论

      本文标题:LeetCode每日一题:length of last word

      本文链接:https://www.haomeiwen.com/subject/vbhafxtx.html