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Python 基础语法

Python 基础语法

作者: 沧海一粟谦 | 来源:发表于2018-06-25 10:57 被阅读1次
    Anne Hathaway

    Python 开发环境搭建

    • Anaconda 安装
    • Sublime 安装

    Python 使用缩进方式分割代码块

    '''
    多行注释
    可以多行描述
    '''
    
    # 单行注释
    
    for i in range(10):
      if i % 2 == 0:
        print(i)
    

    模块导入

    # 导入所有模块
    import datetime
    
    datetime.datetime.now()
    
    # 只导入指定部分
    from datetime import datetime
    datetime.now()
    

    函数

    def double(x):
      return x * 2
    
    result = double(3)
    print(result)
    

    字符串

    # 字符串用单引号、双引号都可以,但需要配对
    str1 = 'What's is your name?' #wrong
    str2 = "What's your name?"
    print("str2=%s, len=%d" % (str2, len(str2)))
    

    异常 (发生意外情况,需要进行处理,否则崩溃)

    try:
      print(0 / 0)
    except ZeroDivisionError:
      print(u"不能被零除")
    

    列表 (list,类似其他语言数组)

    list1 = [1, 2, 3]
    list2 = ["str", 0.5, 4, True]
    list3 = [list1, list2, []]
    print(len(list1))
    print(sum(list1))
    
    # 取值赋值
    x = list(range(10)) # 生成列表[0, 1, ..., 9]
    zero = x[0]
    nine = x[-1]
    eight = x[-2]
    x[0] = -1
    
    # 切取列表
    first_three = x[:3] # [-1, 1, 2]
    three_to_end = x[3:] # [3, 4, ..., 9]
    one_to_four = x[1:5] # [1, 2, 3, 4]
    last_three = x[-3:] # [7, 8, 9]
    without_first_and_last = x[1:-1] # [1, 2, ..., 8]
    copy_of_x = x[:]
    
    # in操作符
    1 in [1, 2, 3] # True
    
    # 连接列表
    x = [1, 2, 3]
    x.extend([4, 5, 6])   # x是[1, 2, 3, 4, 5, 6]
    
    # 不改变原列表
    x = [1, 2, 3]
    y = x + [4, 5, 6]
    
    # 添加元素
    x = [1, 2, 3]
    x.append(4)
    
    # 提取值
    x1, x2 = [1, 2]
    _, x2 = [1, 2]
    

    元组 (tuple, 与列表不一样的地方,不能修改)

    my_tuple = (1, 2, 3)
    my_tuple[0] = -1
    
    # 元组是通过函数返回多个值的好方法
    def sum_and_multi(x, y):
      return (x + y), (x * y)
    
    sp = sum_and_multi(3, 5)
    

    字典 dict

    empty_dict = {}
    grades = {"Jon": 80, "Carmack": 90}
    
    # 取值
    carmack_grade = grades["Carmack"]
    sophie_grade = grades["Sophie"] # Error
    has_sophie = "Sophie" in grades  # False
    sophie_grade = grades.get("Sophie") # None
    sophie_grade = grades.get("Sophie", 0) # 0
    
    # 赋值
    grades["Jon"] = 95
    grades["Sophie"] = 70
    
    # 字典排序
    # 按值倒序
    result = sorted(grades.items(), key=lambda x: x[1], reverse=True)
    
    # 字典可表示结构化数据
    one_post = {
      "post_id": 101,
      "title": u"中美贸易战",
      "post_user_id": 5,
      "tags": [u"新闻", u"美国", u"特朗普"],
    }
    
    one_post.keys()
    one_post.values()
    one_post.items()
    

    集合 set 一组不同的元素

    s = set()
    s.add(1)
    s.add(2)
    s.add(2)
    
    x = 2 in s
    y = 3 in s
    
    list1 = [1, 2, 3, 1, 2, 3]
    set1 = set(list1)
    

    控制流

    # 条件语句
    if 1 > 2:
      print("no")
    elif 2 > 3:
      print("no")
    else:
      print("yes")
    
    print("yes") if 7 % 2 == 0 else "no"
    
    # while循环
    x = 0
    while x < 10:
      print("x = %d" % x)
      x += 1
    
    # for in 更常用
    for x in range(10):
      print("x = %d" % x)
    
    # continue, break
    for x in range(10):
      if x == 2:
        continue   # 进入下一个迭代
      if x == 5:
        break      # 退出循环  
      print("x = %d" % x)
    

    正则表达式

    import re
    
    # 去掉标点符号
    string = re.sub("[\s+\.\!\/_,$%^*(+\"\']+|[+——!,。??、~@#¥%……&*()]+", "", contents)
    

    读写文件

    #读文件
    with open(file_name, "r", encoding="utf-8") as f:
        contents = f.read()
    
    with open(file_name, "w", encoding="utf-8") as f:
        f.write("write content")
    

    统计文章字数出现频率

    with open("D:\\APIcloud\\word.txt","r",encoding="utf-8") as f:
        contents = f.read()
        print(contents)
        result_dict={}
        for w in contents:
            if w in result_dict:
                result_dict[w] +=1
            else:
                result_dict[w] =1
        result = sorted(result_dict.items(),key=lambda x:x[1],reverse=True)
        print(result)
    

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