【C#】基于JsonConvert解析Json数据

1 解析字典

1）解析为 JObject

private void ParseJson() { // 解析为JObject
    string jsonStr = "{'name': 'zhangsan', 'sex': 'male', 'age': 23}";
    JObject jo = JsonConvert.DeserializeObject<JObject>(jsonStr);
    print("name=" + jo["name"] + ", sex=" + jo["sex"] + ", age=" + jo["age"]);
}

说明：需要使用以下命名空间：

using Newtonsoft.Json;
using Newtonsoft.Json.Linq;

2）解析为 Dictionary

private void ParseJson() { // 解析为Dictionary<string, object>
    string jsonStr = "{'name': 'zhangsan', 'sex': 'male', 'age': 23}";
    Dictionary<string, object> dict = JsonConvert.DeserializeObject<Dictionary<string, object>>(jsonStr);
    print("name=" + dict["name"] + ", sex=" + dict["sex"] + ", age=" + dict["age"]);
}

3）解析为封装类

class Student {
    public string name;
    public string sex;
    public int age;
    public override string ToString() {
        return "{name: " + name + ", sex: " + sex + ", age: " + age + "}";
    }
}
    
private void ParseJson() { // 解析为Student
    string jsonStr = "{'name': 'zhangsan', 'sex': 'male', 'age': 23}";
    Student stu = JsonConvert.DeserializeObject<Student>(jsonStr);
    print("stu=" + stu);
}

2 解析一维数组

1）解析为 JArray

private void ParseJson() { // 解析一维数组(JArray)
    string jsonStr = "[1, 2, 3, 4, 5]";
    JArray ja = JsonConvert.DeserializeObject<JArray>(jsonStr);
    print(GetJArrayString(ja));
}

private string GetJArrayString(JArray ja) {
    string str = "[";
    if (ja != null && ja.Count > 0) {
        str += ja[0];
    }
    for (int i = 1; i < ja.Count; i++) {
        str += ", " + ja[i];
    }
    return str + "]";
}

2）解析为数组

private void ParseJson() { // 解析一维数组(int[])
    string jsonStr = "[1, 2, 3, 4, 5]";
    int[] arr = JsonConvert.DeserializeObject<int[]>(jsonStr);
    print(GetArrString(arr));
}

private string GetArrString(int[] arr) {
    string str = "[";
    if (arr != null && arr.Length > 0) {
        str += arr[0];
    }
    for (int i = 1; i < arr.Length; i++) {
        str += ", " + arr[i];
    }
    return str + "]";
}

3）解析为列表

private void ParseJson() { // 解析一维数组(List<int>)
    string jsonStr = "[1, 2, 3, 4, 5]";
    List<int> list = JsonConvert.DeserializeObject<List<int>>(jsonStr);
    print(GetListString(list));
}

private string GetListString(List<int> list) {
    string str = "[";
    if (list != null && list.Count > 0) {
        str += list[0];
    }
    for (int i = 1; i < list.Count; i++) {
        str += ", " + list[i];
    }
    return str + "]";
}

3 解析二维数组

1）解析为 JArray

private void ParseJson() { // 解析二维数组(JArray)
    string jsonStr = "[[1, 2], [3, 4], [5, 6]]";
    JArray ja2 = JsonConvert.DeserializeObject<JArray>(jsonStr);
    print(GetJArrayString2(ja2));
}

private string GetJArrayString2(JArray ja2) {
    string str = "[";
    if (ja2 != null && ja2.Count > 0) {
        str += GetJArrayString((JArray)ja2[0]);
    }
    for (int i = 1; i < ja2.Count; i++) {
        str += ", " + GetJArrayString((JArray)ja2[i]);
    }
    return str + "]";
}

说明：GetJArrayString 方法见 2 1）节。

2）解析为二维数组

private void ParseJson() { // 解析二维数组(int[][])
    string jsonStr = "[[1, 2], [3, 4], [5, 6]]";
    int[][] arr = JsonConvert.DeserializeObject<int[][]>(jsonStr);
    print(GetArrString2(arr));
}

private string GetArrString2(int[][] arr) {
    string str = "[";
    if (arr != null && arr.Length > 0) {
        str += GetArrString(arr[0]);
    }
    for (int i = 1; i < arr.Length; i++) {
        str += ", " + GetArrString(arr[i]);
    }
    return str + "]";
}

说明：GetArrString 方法见 2 2）节。

4 解析数组字典

1）解析为 JObject-JArray

private void ParseJson() { // "数组字典"混合解析(JObject-JArray)
    string jsonStr = "{'vec1': [1, 2, 3, 4], 'vec2': [[1, 2], [3, 4], [5, 6]]}";
    JObject jo = JsonConvert.DeserializeObject<JObject>(jsonStr);
    print("vec1=" + GetJArrayString((JArray) jo["vec1"]) + ", vec2=" + GetJArrayString2((JArray) jo["vec2"]));
}

说明： GetJArrayString 方法见 2 1）节，GetJArrayString2 方法见 3 1）节。

2）解析为封装类

class VecInfo {
    public int[] vec1;
    public int[][] vec2;
}

private void ParseJson() { // "数组字典"混合解析(封装类)
    string jsonStr = "{'vec1': [1, 2, 3, 4], 'vec2': [[1, 2], [3, 4], [5, 6]]}";
    VecInfo vecInfo = JsonConvert.DeserializeObject<VecInfo>(jsonStr);
    print("vec1=" + GetArrString(vecInfo.vec1) + ", vec2=" + GetArrString2(vecInfo.vec2));
}

说明： GetArrString 方法见 2 2）节，GetArrString2 方法见 3 2）节。

5 解析字典数组

1）解析为 JArray-JObject

private void ParseJson() { // "字典数组"混合解析(JArray-JObject)
    string jsonStr = "[{'name': 'xiaomin', 'sex': 'male', 'age': 23}, {'name': 'xiaohong', 'sex': 'female', 'age': 21}]";
    JArray ja = JsonConvert.DeserializeObject<JArray>(jsonStr);
    string str = "[";
    if (ja.Count > 0) {
        str += "{name: " + ja[0]["name"] + ", sex: " + ja[0]["sex"] + ", age: " + ja[0]["age"] + "}";
    }
    for (int i = 1; i < ja.Count; i++) {
        str += ", {name: " + ja[i]["name"] + ", sex: " + ja[i]["sex"] + ", age: " + ja[i]["age"] + "}";
    }
    str += "]";
    print(str);
}

2）解析为数组封装类

private void ParseJson() { // "字典数组"混合解析(Student[])
    string jsonStr = "[{'name': 'xiaomin', 'sex': 'male', 'age': 23}, {'name': 'xiaohong', 'sex': 'female', 'age': 21}]";
    Student[] stus = JsonConvert.DeserializeObject<Student[]>(jsonStr);
    print(GetStudentArrString(stus));
}

private string GetStudentArrString(Student[] stus) {
    string str = "[";
    if (stus != null && stus.Length > 0) {
        str += stus[0];
    }
    for (int i = 1; i < stus.Length; i++) {
        str += ", " + stus[i];
    }
    return str + "]";
}

说明：Student 类见 1 3）节。

3）解析为列表封装类

private void ParseJson() { // "字典数组"混合解析(List<Student>)
    string jsonStr = "[{'name': 'xiaomin', 'sex': 'male', 'age': 23}, {'name': 'xiaohong', 'sex': 'female', 'age': 21}]";
    List<Student> list = JsonConvert.DeserializeObject<List<Student>>(jsonStr);
    print(GetStudentListString(list));
}

private string GetStudentListString(List<Student> list) {
    string str = "[";
    if (list != null && list.Count > 0) {
        str += list[0];
    }
    for (int i = 1; i < list.Count; i++) {
        str += ", " + list[i];
    }
    return str + "]";
}

6 解析 Vector3 点集

1）字典格式点

private void ParseJson() {
    string jsonStr = "[{'x': 1, 'y': 2, 'z': 3}, {'x': 4, 'y': 5, 'z': 6}, {'x': 7, 'y': 8, 'z': 9}]";
    Vector3[] points = JsonConvert.DeserializeObject<Vector3[]>(jsonStr);
    print(GetVectorString(points));
}

private string GetVectorString(Vector3[] points) {
    string str = "[";
    if (points != null && points.Length > 0) {
        str += points[0];
    }
    for (int i = 1; i < points.Length; i++) {
        str += ", " + points[i];
    }
    return str + "]";
}

2）数组格式点

private void ParseJson() {
    string jsonStr = "[[1, 2, 3], [4, 5, 6], [7, 8, 9]]";
    float[][] arr = JsonConvert.DeserializeObject<float[][]>(jsonStr);
    Vector3[] points = new Vector3[arr.Length];
    for(int i = 0; i < arr.Length; i++) {
        points[i] = new Vector3(arr[i][0], arr[i][1], arr[i][2]);
    }
    print(GetVectorString(points));
}

说明：GetVectorString 方法同第 1）节。

7 从文件中解析

private void ParseJson() { // 解析为JObject
    string jsonStr = File.ReadAllText("Assets/Scenes/Student.json", Encoding.UTF8);
    JObject jo = JsonConvert.DeserializeObject<JObject>(jsonStr);
    print("name=" + jo["name"] + ", sex=" + jo["sex"] + ", age=" + jo["age"]);
}

说明：File 和 Encoding.UTF8 需要引入命名空间 System.IO、System.Text。

Student.json

{'name': 'zhangsan', 'sex': 'male', 'age': 23}

声明：本文转自【C#】基于JsonConvert解析Json数据